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40 women can do a piece of work in 15 days. How many more women would be required to do the same work in 10 days?
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efficiency of a woman = 1/600 For doing 1/10th of a work in a day let’s say total x women are required Hence, x/600 = 1/10 x=60 Hence, 20 more women are required
A certain amount invested at compound interest doubles itself in 3 years. After how many years the sum will be 16 times the original amount?
==> It takes 12 years for the sum to become 16 times its original value.
Sheetal bought a scooter at Rs. 32,000 and sold it at a profit of 30%. With the amount that's obtained, she purchased another scooter and sold it at a loss of 25%. What is her net profit or loss?
The selling price of the first scooter = 32000 * 1.3 = 41600 The selling price of the second scooter = 41600 * .75 = 31200 So, her net loss = 32000 - 31200 = Rs. 800
An amount of Rs. 2430 is divided among A, B and C such that if their shares be reduced by 5, 10 and 15 respectively, the remainders shall be in the ratio of 3 : 4 : 5. Then, B’s share was
If the shares of the three persons are decreased, the total amount being distributed goes down by 5+10+!5 = 30
So, amount to be distributed = 2400 B's new share = 4/12 * 2400 = 800
So, B's original share = 800 + 10 = Rs 810
Two trains moving in the opposite direction with speeds of 30m/s and 50m/s cross each other in 12 seconds. If the length of the slower train is 450 m, then what is the length of the faster train?
Let L2 be the length of the faster train. Since, the trains are moving opposite to each other the net relative speed = 30 + 50 = 80m/s The total distance covered by the trains to cross each other = 450 + L2 Applying TSD relation we get, 80 = ( 450 + L2)/12 L2 + 450 = 960 => L2 = 510m
Directions For Questions
The following table provides the information on the marks scored by six students in six subjects.
The following table gives the information on the maximum marks in each subject.
...view full instructions
What is the percentage of average marks obtained by all the six students in chemistry?
Sum of the marks obtained by all the six students in chemistry = 50+45+42+53+55+48=293 Average marks = (293/6) =48.83. Maximum marks in chemistry = 60. Percentage = (48.83/60)*100 = 81.39%
The total of the marks obtained by Pavan is what percentage less than the total maximum marks?
Marks obtained by Pavan = 72+52+42+92+68+82 =408 Maximum marks = 75+60+60+100+100+100 =495 Required percentage = (495-408)/495 = 17.6%
Who among the six students scored the highest total marks?
Total marks scored by Athul =400 Midhun - 370 Pavan - 408 Naveen - 433 Karthik - 409 Charan - 402 Therefore the correct option to choose is D.
The sum of the marks obtained by Karthik in physics and chemistry is what percentage of the total marks scored by Midhun?
Total marks scored by Midhun = 370 Marks scored by Karthik in physics and chemistry = 58+55 =113 Required percentage = (113/370)*100 = 30.54%
What is the difference (in percentage points) between the percentages of total marks obtained by Pavan and Charan?
Overall percentage obtained by Pavan = (408/495)*100 = 82.42% Overall percentage obtained by Charan = (402/495)*100 =81.21% The difference = 1.21%
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