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Find the value of the following expressions.
60% of 50% of 40% of 30% of 1000 = ?
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30% of 1000 = 300 40% of 300 = 120 50% of 120 = 60 60% of 60 = 36
103*97 = ?
103 = 100+3 97 = 100 - 3 => (100 + 3)( 100 - 3) = 1002 - 32 = 10000 - 9 = 9991
40% of 1500 - 30% of 1200 = ?
40% of 1500 = .4*1500 = 600 30% of 1200 = .3*1200 = 360 => 40% of 1500 - 30% of 1200 = 600 - 360 = 240.
Find the approximate value of the number which should replace (?) in the following questions.
66.5% of 426 = ?
66.5% of 426 ≈ 66.66% of 426 = (2/3) X 426 = 284 which is closest to D.
1302 = 16900 and 1402 = 19600 So, (?) must be between 130 and 140. Now, let us approximately calculate 1352 which is 1302 + 2 × 5 × 130 + 25 which is definitely more 16900 + 1300 = 18200. Thus, (?) must be between 130 and 135. Only, A is in this range.
(0.1111)2 × 728 × 16 = ?
(0.1111)2 × 728 × 16 ≈ (1/9 )2 × 729 × 16 = 144
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