Step1: 6L water, 4L acid

4L will contain: 2.4L water, 1.6L acid

Step2: water = 6L - 2.4L = 3.6L

Acid = 10 - 3.6 = 6.4L

Percentage of acid = 6.4 * 100 /10 = 64%.

Or

The replacing acid is 40% of the total quantity.

So in final mixture the amount of water is

10/100 * 60/100 * 60 = 3.6 liters

The amount of acid is,

10 – 3.6 = 6.4 liters

Required % = 6.4/10 * 100 = 64%\

Let the length and breadth of the rectangle be l and b respectively.

The perimeter = 2l+ 2b cm

The perimeter of the new rectangle = 2(l + 12) + 2(b + 8) = 2l + 2b + 40

Without knowing the value of l and b, we could not determine the required answer

Total profit = 1250

Share of A in profit = 600

Share of B in profit = 1250 - 600 = 650

Profit ratio, A: B = 600: 650 = 12: 13

Investment of A = 7200

Let investment of B = a

Period of investment of A = 12 months

Period of investment of 8 = 12 - 2 = 10 months

Profit ratio, A: B = 7200 * 12: a * 10 = 8640: a

Then, 12:13 = 8640: a

a = Rs.9360

Let 'a' and 'b' are number of oranges and apples respectively.

Oranges sold to A = 20/100 * a = 0.2 a

Oranges sold to B = (a – 0.2a) * 40/100 = 0.32 a

Remaining number of oranges = a – (0.2a + 0.32 a) = 0.48 a

=> 48 = 0.48 a

=> 100 = a

Apples sold to A = 40/100 * b = 0.4 b

Remaining number of Apples = 10/100 * b =0.1 b

Apples sold to B = 100

=> 100 = b – (0.4 b + 0.1 b)

=> 100 = 0.5 b

=> 200 = b

Total number of apples and oranges = a + b = 100 + 200 = 300

Or

Short cut:

Let 'a' and 'b' are number of oranges and apples respectively.

48 = 60% of (100 - 20)% of a

a = 100

100 = (100 - 40 - 10)% of b

b = 200

Total apples and oranges = 100 + 200 = 300

S.P of 8 articles = C.P of 10 articles

S.P of 1 article = C.P of (5/4) article

Let C.P of 1 article be Rs 4

S.P of 1 article = (5/4)*4 = Rs. 5

So, percentage profit = ((5 - 4)/4)*100% = 25%

SI = 3422 - 2900 = 522

Rate = SI * 100/(P * time) = 522 * 100/(2900 * 3) = 6%

New rate = 6 + 3 = 9%

New SI = 2900 * 9 * 3/100 = Rs. 783

Amount = P + SI = 2900 + 783 = 3683

Let the speeds of Jagan and Josh be 3k km/hr and 4k km/hr

Relative speed = 3k + 4k = 7k km/hr

So, 7k * (3/60) = 4.2

=> k = 12

Difference between their speeds = 4k - 3k = 12 km/hr

Let leak empty it in x hours, then

1/10 - 1/x = 1/12

Or, x = 60 hours

Let the present age of Subha, Prasanth and Santhi is 'x', 'y' and 'z' respectively.

(x + y + z)/3 =23

(x + y + z) = 69.... (1)

y = 2Z ... (2) From (1) and (2):

x + 3z = 69....(3)

x - z = 9....(4)

From (3) and (3):

4x = 96

x = 24 years

Investment of Mano = 3200

Investment of Varthan = 4800

Period of investment of Mano = 40% of 12 = 4.8 months

Period of investment of Varthan = 12 - 4.8 = 7.2 months

Profit ratio, Mano: Varthan = 3200 * 4.8: 4800 * 7.2 = 4: 9