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SBI Clerk 2020 Aptitude Test - 6
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SBI Clerk 2020 Aptitude Test - 6
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  • Question 1/10
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    Directions For Questions

    The following line graph shows number of three books sold in five cities.

    ...view full instructions

    Number of Book A sold in Pune is what percent of the number of Book C sold in Mumbai?

    Solutions

    Number of Book A sold in Pune = 450

    Number of Book C sold in Mumbai = 500

    Required percentage = 450/500 * 100 = 90%

     

  • Question 2/10
    1 / -0

    Directions For Questions

    The following line graph shows number of three books sold in five cities.

    ...view full instructions

    Find the respective ratio of number of Book B sold in Mumbai and number of Book A sold in Delhi.

    Solutions

    Number of Book B sold in Mumbai = 420

    Number of Book A sold in Delhi = 360

    Required ratio = 420: 360 = 7: 6

     

  • Question 3/10
    1 / -0

    Directions For Questions

    The following line graph shows number of three books sold in five cities.

    ...view full instructions

    Find the total number of all books sold in Chennai.

    Solutions

    Number of Book A sold in Chennai = 420

    Number of Book B sold in Chennai = 540

    Number of Book C sold in Chennai = 440

    Total number of all books sold in Chennai = 420 + 540 + 440 = 1400

     

  • Question 4/10
    1 / -0

    Directions For Questions

    The following line graph shows number of three books sold in five cities.

    ...view full instructions

    Find the difference between number of Book B sold in Delhi and number of Book C sold in Pune.

    Solutions

    Number of Book B sold in Delhi = 460

    Number of Book C sold in Pune = 480

    Required difference = 480 - 460 = 20

     

  • Question 5/10
    1 / -0

    Directions For Questions

    The following line graph shows number of three books sold in five cities.

    ...view full instructions

    Number of Book C sold in Bangalore is what percent more than the number of Book A sold in the same city?

    Solutions

    Number of Book C sold in Bangalore = 500

     Number of Book A sold in Bangalore = 250

    Required percentage = (500 - 250)/250 * 100

    = 250/250 * 100

    = 100%

     

  • Question 6/10
    1 / -0

    Directions For Questions

    In each question, two equations numbered I and II are given. You have to solve both the equations and mark an appropriate answer.

    a)  x < y 

    b)  x ≥ y

    c)  x > y

    d)  x ≤ y

    e)  Relation between x and y can’t be established

    ...view full instructions

    I. 9x2 – 29x + 22 = 0

    II. 6y2 – 31y + 39 = 0

    Solutions

    I. 9×2 – 29x + 22 = 0

    x = (-18/9), (-11/9)

    x = 2, 11/9

    II. 6y2 – 31y + 39 = 0

    y = (-18/6), (-13/6)

    y = 3, 13/6

    Hence x< y

     

  • Question 7/10
    1 / -0

    Directions For Questions

    In each question, two equations numbered I and II are given. You have to solve both the equations and mark an appropriate answer.

    a)  x < y 

    b)  x ≥ y

    c)  x > y

    d)  x ≤ y

    e)  Relation between x and y can’t be established

    ...view full instructions

    I. x2 = 11449

    II. y = √11449

    Solutions

    I. x2 = 11449

    x = √11449 = ±107

    II. y = √11449 = 107

    Hence x ≤ y

     

  • Question 8/10
    1 / -0

    Directions For Questions

    In each question, two equations numbered I and II are given. You have to solve both the equations and mark an appropriate answer.

    a)  x < y 

    b)  x ≥ y

    c)  x > y

    d)  x ≤ y

    e)  Relation between x and y can’t be established

    ...view full instructions

    I. 6x2– 25x – 14 = 0

    II. 8y2– 35y + 12 = 0

    Solutions

    I. 6×2 – 25x – 14 = 0

    x = (3/6), (-28/6)

    x = -1/2, 14/3

    II. 8y2 – 35y + 12 = 0

    y = (-3/8), (-32/8)

    y = 3/8, 4

    Hence no relation can be established.

     

  • Question 9/10
    1 / -0

    Directions For Questions

    In each question, two equations numbered I and II are given. You have to solve both the equations and mark an appropriate answer.

    a)  x < y 

    b)  x ≥ y

    c)  x > y

    d)  x ≤ y

    e)  Relation between x and y can’t be established

    ...view full instructions

    I. 5x – 4y = 83

    II. 6x + 3y = 45

    Solutions
    1. 5x – 4y = 83     ..(i)
    2. 6x + 3y = 45      …(ii)

    Solving equation (i)×3 + (ii)×4, we get

    (15x – 12y = 249) + (24x + 12y = 180)

    x = (429/39) = 11

    Putting the value of x in equation (i), we get

    55 – 4y = 83

    -4y = 83-55

    y = -28/4 = -7

    Hence x> y

     

  • Question 10/10
    1 / -0

    Directions For Questions

    In each question, two equations numbered I and II are given. You have to solve both the equations and mark an appropriate answer.

    a)  x < y 

    b)  x ≥ y

    c)  x > y

    d)  x ≤ y

    e)  Relation between x and y can’t be established

    ...view full instructions

    I. 9x2 + 6√7 x + 7 = 0

    II. 4y2 + 4√3 y + 3 = 0

    Solutions

    I. 9x2+ 6√7 x + 7 = 0

    Or, (3x + √7)2 = 0

    Or, 3x = -√7

    x = -3/√7

    II. 4y2 + 4√3 y + 3 = 0

    Or, (2y + √3)2 = 0

    Or, 2y = -√3

    y = -√3/2

    Hence x< y

     

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