Please wait...

SBI Clerk 2020 Aptitude Test - 11
Menu grid icon
Result Result point icon
SBI Clerk 2020 Aptitude Test - 11
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x > y

    b) If x ≥ y

    c) If x < y

    d) If x ≤ y

    e) If x = y or the relation cannot be established.

    ...view full instructions

    I) x2 + 26x + 153=0

    II) y2 + 117=406

    Solutions

    x2 + 26x + 153 = 0

    x2 + 17x + 9x + 153 = 0

    x(x + 17) + 9(x + 17) = 0

    (x + 9)(x + 17) = 0

    x = -17, -9

    y2 + 117 = 406

    y2 = 289

    y = -17, 17

    Relationship cannot be established between x and y.

     

  • Question 2/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x > y

    b) If x ≥ y

    c) If x < y

    d) If x ≤ y

    e) If x = y or the relation cannot be established.

    ...view full instructions

    I) 2x2 - 24x + 64=0

    II) y2 – 12y + 32=0

    Solutions

    2x2 - 24x + 64=0

    2x2 – 16x – 8x + 64=0

    2x(x – 8) – 8(x – 8)=0

    (2x – 8)(x – 8)=0

    x = 4, 8

    y2 – 12y + 32=0

    y2 – 8y – 4y + 32=0

    y(y – 8) – 4(y – 8)=0

    (y – 4)(y – 8)=0

    y= 4, 8

    Relationship cannot be established between x and y.

     

  • Question 3/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x > y

    b) If x ≥ y

    c) If x < y

    d) If x ≤ y

    e) If x = y or the relation cannot be established.

    ...view full instructions

    I) x + y = 45

    II) x – 2y = 15

    Solutions

    x + y =45 ------(1)

    x – 2y =15 -----------(2)

    (1) – (2)

    3y=30

    y = 10

    x = 45 – 10=35

    Hence, x > y

     

  • Question 4/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x > y

    b) If x ≥ y

    c) If x < y

    d) If x ≤ y

    e) If x = y or the relation cannot be established.

    ...view full instructions

    I) 4x + 132=1156

    II) 5y = 15625

    Solutions

    4x + 132 = 1156

    4x = 1024

    4x = (4)5   

    x = 5

    5y = 15625

    5y = (5)6     

    y = 6

    Hence, x < y

     

  • Question 5/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x > y

    b) If x ≥ y

    c) If x < y

    d) If x ≤ y

    e) If x = y or the relation cannot be established.

    ...view full instructions

    I) x2 + 18x + 80=0

    II) y2 + 21y + 104=0

    Solutions

    x2 + 18x + 80=0

    x2 + 10x + 8x + 80=0

    x(x + 10) + 8(x + 10)=0

    (x + 8)(x + 10)=0

    x = -8, -10

    y2 + 21y + 104=0

    y2 + 13y + 8y + 104=0

    y(y + 13) + 8(y + 13)=0

    (y + 8)(y + 13)=0

    y = -8, -13

    Relationship cannot be established between x and y.

     

  • Question 6/10
    1 / -0

    Rahul invests Rs.1800 at simple interest for four years. After 4 years he received the total amount Rs.2880. If the rate of interest increased by 5%, how much amount received by Rahul after 5 years?

    Solutions

    SI = P * N * R/100

    2880 – 1800 = 1800 * 4 * R/100

    R = 15%

    5% of rate of interest is increased, So R=20%

    SI = 1800 * 20 * 5/100

    = 1800

    Rahul received the total amount = 1800 + 1800 = 3600

     

  • Question 7/10
    1 / -0

    A’s age 8 years ago is equal to B’s age 6 years ago. If the ratio of the sum of the ages of A and B 5 years ago together to C’s present age is 2:1 and C’s age 6 years hence is equal to A’s present age. What is the present age of C?

    Solutions

    A – 8 = B – 6

    A – B = 2

    (A - 5 + B - 5)/C = 2/1

    A + B  = 2C + 10

    C + 6 = A

    B = A – 2

    B = C + 6 – 2

    B = C + 4

    C + 4 + C + 6 = 2C + 10

    We cannot find the answer.

     

  • Question 8/10
    1 / -0

    The average mark of A, B, C and D is 84 and the average mark of B, C and D is 70. If the sum of the mark of A and C is 180, then what is the average mark of B and D?

    Solutions

    A + B + C + D = 84 * 4 = 336

    B + C + D = 70 * 3 = 210

    A = 336 – 210 = 126

    C = 180 – 126 = 54

    B + D = 210 – 54 = 156

    Average of B and D = 156/2 = 78

     

  • Question 9/10
    1 / -0

    A train crosses the x m long platform in 36 seconds and crosses the man standing in a platform in 12 seconds. If the train crosses the man running in opposite direction at the speed of 20 kmph in 9 seconds, find the value of x?

    Solutions

    Length of the train = z

    Speed of train= y

    z = y * 5/18 * 12

    3z = 10y

    z = (y + 20) * 5/18 * 9

    2z = 5y + 100

    4z = 3z + 200

    z = 200 m

    y = 3 * 200/10 = 60 kmph

    200 + x = 60 * 5/18 * 36

    x = 600 – 200

    x = 400 m

     

  • Question 10/10
    1 / -0

    If the area of the trapezium is 126 cm2 and the base of the trapezium is 16 cm and 12 cm respectively, then what is the height of the trapezium?

    Solutions

    Area of the trapezium = 1/2(a + b) * h

    126 = 1/2 * (16 + 12) * h

    h = 9 cm

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now