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LIC AAO & AE 2020 Aptitude Test - 6
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LIC AAO & AE 2020 Aptitude Test - 6
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  • Question 1/10
    1 / -0

    If the ratio of the speed of boat in still water and the speed of the boat in upstream is 2:1 and the speed of stream is 5 kmph, then find the distance travelled downstream and upstream in 8 hours?

    Solutions

    From question we observe that,

    x=2x-5

    (i.e) x=5 kmph

    Then, Speed of the boat in still water=2 * 5= 10 kmph

    Upstream speed=1* 5=5 kmph

    Speed of the boat in downstream =10 + 5=15 kmph

    Thus, x/15 + x/5=8

    x=30 km

     

  • Question 2/10
    1 / -0

    Ram invested Rs.x in scheme A which is offering simple interest at 15% per annum and also he invested Rs.(x + 2000) in scheme B which is offering simple interest at 12% per annum. After 4 years the difference between the interests received by both scheme is Rs.480, then find the value of x.

    Solutions

    Scheme A=x * 15 * 4/100=3x/5

    Scheme B=(x + 2000) * 12 * 4/100=(12x + 24000)/25

    According to the question,

    3x/5 – (12x +24000)/25 =480

    15x – 12x – 24000=12000

    3x=36000

    x=Rs.12000

     

  • Question 3/10
    1 / -0

    If the ratio of the ages of A and B is 5:3 and the ratio of the ages of B and C is 7:9. The difference between the ages of A and C is 8 years. What is B’s age after 20 years?

    Solutions

    A:B:C=35:21:27

    Given that,

    A - C=35x-27x=8

    (i.e) x=1

    Thus, B’s age=21*1=21 years

    After 20 years, B’s age=21 + 20=41 years

     

  • Question 4/10
    1 / -0

    The side of the square is 60% of the length of the rectangle and the perimeter of the rectangle is 60 cm. If the ratio of the length to breadth of the rectangle is 2:1, then what is the perimeter of the square?

    Solutions

    Perimeter of the rectangle=60 cm

    (i.e) 3x * 2=60

    x=10 cm

    Then, Length of the rectangle=10 * 2=20 cm

    Side of the square=20 * 60/100=12 cm

    Perimeter of the square=12 * 4= 48 cm

     

  • Question 5/10
    1 / -0

    A’s annual salary is Rs.4.80 lakh. In a month he spends 20% of his salary on house rent, 40% of the remaining to education fee and Rs.2000 in insurance. What is the amount left with him in a first month?

    Solutions

    Monthly salary of A=480000/12=40000

    House rent=20/100 * 40000=8000

    Remaining=40000-8000=32000

    Education fee=32000 * 40/100=12800

    Insurance=Rs.2000

    Remaining amount=32000-12800-2000=Rs. 17200

     

  • Question 6/10
    1 / -0

    A can do the piece of work in 24 days, B is 5/6 more efficient than A and C alone compete the work in 30 days. In how many days A, B and C together can complete the work?

    Solutions

    A=1/24

    B=5/6 *24=20 days (i.e) B=1/20

    C=1/30

    A+B+C=1/24 + 1/20 +1/30

    = (10 + 12 + 8/)240

    =30/240

    =1/8

     

  • Question 7/10
    1 / -0

    The pack has 52 cards. If two cards are drawn one by one without replacement, then find the probability that both of them are queens.

    Solutions

    Required probability=4/52 * 3/51=1/221

     

  • Question 8/10
    1 / -0

    Two trains of equal length are running in opposite direction at the speed of 50 kmph and 70 kmph respectively. If the faster train crosses the slower train in 12 seconds, then what is the length of train?

    Solutions

    According to the question,

    x + x=(50 + 70) *5/18 *12

    2x=400

    x=200 m

     

  • Question 9/10
    1 / -0

    A and B started the business with investment in the ratio of 3:4 and after four month C joined with the half of the investment of B. After another 4months A and C added Rs.2000 and Rs.3000 respectively with his initial investment. At the end of one year the total profit is Rs.6600 and the profit share of B is Rs.2400. What is initial investment of A?

    Solutions

    Profit ratio=((3x * 8) + (3x + 2000) *4) : (4x *12) : ((2x * 4) + (2x +3000)*4)

    =(36x + 8000) : 48x : (16x + 12000)

    Then, 48x/(100x + 20000)=2400/6600

    132x=100x+20000

    x=625

    Thus, investment of A=625 * 3=Rs. 1875

     

  • Question 10/10
    1 / -0

    The cost price of Watch and Shirt is equal. The shopkeeper gets the profit of 20% on Watch and the selling price of the shirt is 10% less than that of watch. What is the overall profit percentage?

    Solutions

    Let CP=100x

    Then, SP of Watch=100x * 120/100=120x

    SP of shirt=120x * 90/100=108x

    Profit of shirt=108x-100x=8x

    Total profit=8x + 20x=28x

    Required %=28x/200x *100=14%

     

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