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What value should come in the place of (?) in the following number series?
4, 10, 33, 136, ?, 4116
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4 * 2 + 2 = 10
10 * 3 + 3 = 33
33 * 4 + 4 = 136
136 * 5 + 5 = 685
685 * 6 + 6 = 4116
1944, 968, 480, 236, 114, ?
1944/2 – 4 = 968
968/2 – 4 = 480
480/2 – 4 = 236
236/2 – 4 = 114
114/2 – 4 = 53
35, 49, 63, 77, 91, ?
What value should come in the place of (?) in the following number series?`
88, 165, 220, 253, ?
88 + 77 = 165
165 + 55 = 220
220 + 33 = 253
253 + 11 = 264
85, 110, 94, 103, 99, ?
85 + 52 = 110
110 – 42 = 94
94 + 32 = 103
103 – 22 = 99
99 + 12 = 100
Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,
Quantity I: What is the perimeter of the rectangle whose area is 216 cm2 and the ratio of length to breadth is 3: 2?
Quantity II: 63 cm
From Quantity I,
Area of the rectangle = 216
3x * 2x = 216
x2 = 36
x = 6 cm
Perimeter of the rectangle = 2 * (3 * 6 + 2 * 6) = 60 cm
From Quantity II,
63 cm
Quantity I < Quantity II
Quantity I: Compound interest on Rs.1800 at 10% per annum for 2 years?
Quantity II: What is the difference between the simple and compound interest on Rs.37800 at 10% per annum for two years?
CI = P (1 + R/100)2 - P
CI = 1800 * (1 + 10/100)2 – 1800
= 378
Difference = 37800 * 10 * 10/(100 * 100)
Quantity I = Quantity II
Quantity I: 18 seconds
Quantity II: Time taken by 180 m train crosses a man at the speed of 20 kmph.
18 seconds
Required time = 180/(20 * 5/18) = 32.4 seconds.
Quantity I: Ratio of the present age of A and B is 4: 5 and after 8 years the ratio becomes 5: 6. What is the difference between the ages of A and B after 15 years?
Quantity II: 6 years
(4x + 8)/(5x + 8) = 5/6
25x + 40 = 24x + 48
x = 8 years
A = 4 * 8 = 32 years
B = 5 * 8 = 40 years
After 15 years A and B’s age is 47 and 55 years respectively.
Difference between the ages of A and B = 8 years
6 years
Quantity I > Quantity II
Quantity I: A and B can complete a work in 10 days and 18 days respectively. If C’s efficiency is 50% more than B, in how many days A, B and C together can complete the work?
Quantity II: 5 days
A = 1/10
B = 1/18
C = 18 * 100/150 = 12 days
A + B + C = 1/10 + 1/18 + 1/12
= (18 + 10 + 15)/180
= 43/180
Required time = 180/43 days
5 days
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