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SBI Clerk 2020 Aptitude Test - 13
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SBI Clerk 2020 Aptitude Test - 13
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  • Question 1/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    4, 10, 33, 136, ?, 4116 

    Solutions

    4 * 2 + 2 = 10

    10 * 3 + 3 = 33

    33 * 4 + 4 = 136

    136 * 5 + 5 = 685

    685 * 6 + 6 = 4116

     

  • Question 2/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    1944, 968, 480, 236, 114, ?

    Solutions

    1944/2 – 4 = 968

    968/2 – 4 = 480

    480/2 – 4 = 236

    236/2 – 4 = 114

    114/2 – 4 = 53

     

  • Question 3/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    35, 49, 63, 77, 91, ?

    Solutions

     

  • Question 4/10
    1 / -0

    What value should come in the place of (?) in the following number series?`

    88, 165, 220, 253, ?

    Solutions

    88 + 77 = 165

    165 + 55 = 220

    220 + 33 = 253

    253 + 11 = 264

     

  • Question 5/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    85, 110, 94, 103, 99, ?

    Solutions

    85 + 52 = 110

    110 – 42 = 94

    94 + 32 = 103

    103 – 22 = 99

    99 + 12 = 100

     

  • Question 6/10
    1 / -0

    Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,

    Quantity I: What is the perimeter of the rectangle whose area is 216 cm2 and the ratio of length to breadth is 3: 2?

    Quantity II: 63 cm

    Solutions

    From Quantity I,

    Area of the rectangle = 216

    3x * 2x = 216

    x= 36

    x = 6 cm

    Perimeter of the rectangle = 2 * (3 * 6 + 2 * 6) = 60 cm

    From Quantity II,

     63 cm

    Quantity I < Quantity II

     

  • Question 7/10
    1 / -0

    Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,

    Quantity I: Compound interest on Rs.1800 at 10% per annum for 2 years?

    Quantity II: What is the difference between the simple and compound interest on Rs.37800 at 10% per annum for two years?

    Solutions

    From Quantity II,

    CI = P (1 + R/100)2 - P

    CI = 1800 * (1 + 10/100)2 – 1800

    = 378

    From Quantity II,

    Difference = 37800 * 10 * 10/(100 * 100)

    = 378

    Quantity I = Quantity II

     

  • Question 8/10
    1 / -0

    Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,

    Quantity I: 18 seconds

    Quantity II: Time taken by 180 m train crosses a man at the speed of 20 kmph.

    Solutions

    From Quantity I,

    18 seconds

    From Quantity II,

    Required time = 180/(20 * 5/18) = 32.4 seconds.

    Quantity I < Quantity II

     

  • Question 9/10
    1 / -0

    Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,

    Quantity I: Ratio of the present age of A and B is 4: 5 and after 8 years the ratio becomes 5: 6. What is the difference between the ages of A and B after 15 years?

    Quantity II: 6 years

    Solutions

    From Quantity I,

    (4x + 8)/(5x + 8) = 5/6

    25x + 40 = 24x + 48

    x = 8 years

    A = 4 * 8 = 32 years

    B = 5 * 8 = 40 years

    After 15 years A and B’s age is 47 and 55 years respectively.

    Difference between the ages of A and B = 8 years

    From Quantity II,

    6 years

    Quantity I > Quantity II

     

  • Question 10/10
    1 / -0

    Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,

    Quantity I: A and B can complete a work in 10 days and 18 days respectively. If C’s efficiency is 50% more than B, in how many days A, B and C together can complete the work?

    Quantity II: 5 days

    Solutions

    From Quantity I,

    A = 1/10

    B = 1/18

    C = 18 * 100/150 = 12 days

    A + B + C = 1/10 + 1/18 + 1/12

    = (18 + 10 + 15)/180

    = 43/180

    Required time = 180/43 days

    From Quantity II,

    5 days

    Quantity I < Quantity II

     

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