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LIC AAO & AE 2020 Aptitude Test - 10
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LIC AAO & AE 2020 Aptitude Test - 10
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  • Question 1/10
    1 / -0

    What is the approximate value should come in place of question mark in the following questions?

    11.111 % of 351.092 + 15.157 % of 79.975 = ? * √2600.891

    Solutions

    39 + 12 = ? * 51

    ? = 1

     

  • Question 2/10
    1 / -0

    What is the approximate value should come in place of question mark in the following questions?

    44.945 % of 59.908 + √3481.081 * 5.902 + 119.119 =?

    Solutions

    27 + 354 + 119 = 0

    500=?

     

  • Question 3/10
    1 / -0

    What is the approximate value should come in place of question mark in the following questions?

    89.904 % of 139.902 + ? * 23.23 + 249.023 = 559.156

    Solutions

    126 + ? * 23 + 249 =559

    ?=8

     

  • Question 4/10
    1 / -0

    What is the approximate value should come in place of question mark in the following questions?

    19.19 % of 199.998 + √360.891 * 38.381 + ? = 825.231

    Solutions

    38 + 722 + ? =825

    ? = 65

     

  • Question 5/10
    1 / -0

    What is the approximate value should come in place of question mark in the following questions?

    123.123 + 219.19 – 378.897 + 537.370 =?

    Solutions

    123 + 219 – 379 + 537 =?

    500 =?

     

  • Question 6/10
    1 / -0

    Directions For Questions

    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    a)Quantity I > Quantity II

    b)Quantity I ≥ Quantity II

    c)Quantity II > Quantity I

    d)Quantity II ≥ Quantity I

    e)Quantity I = Quantity II or Relation cannot be established

    ...view full instructions

    Quantity I: If 12 men working 8 hours a day and earn Rs.600 per day, then 18 men working 6 hours a day will earn how much per day?

    Quantity II: If 36 men can complete the work in 250 days, in how many days will 15 men do it?

    Solutions

    From quantity I,

    12 * 8/600 = 18 * 6/ x

    x=Rs.675

    From quantity II,

    36 * 250 = 15 * x

    X=600 days

     

  • Question 7/10
    1 / -0

    Directions For Questions

    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    a)Quantity I > Quantity II

    b)Quantity I ≥ Quantity II

    c)Quantity II > Quantity I

    d)Quantity II ≥ Quantity I

    e)Quantity I = Quantity II or Relation cannot be established

    ...view full instructions

    Quantity I: (x/21 * x/189) = 1, find x?

    Quantity II:If the inner circumference of the circular race track 7 cm wide is 308 cm, find the radius of the outer circle?

    Solutions

    From quantity I,

    x * x=189 * 21

    x=63,-63

    From quantity II,

    2 * 22 /7 * r =308

    r=49

    Radius of the outer circle= 49 + 7 =56 cm

     

  • Question 8/10
    1 / -0

    Directions For Questions

    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    a)Quantity I > Quantity II

    b)Quantity I ≥ Quantity II

    c)Quantity II > Quantity I

    d)Quantity II ≥ Quantity I

    e)Quantity I = Quantity II or Relation cannot be established

    ...view full instructions

    Quantity I:The average weight of 20 students is 28 kg and one new student Join the class the average weight reduced by1 kg, what is the weight of new student?

    Quantity II: A buys at rate of 2 kg for Rs.14 and sells them at 5 kg for Rs.50. If he earnsRs.24 as profit, then how much he must sell?

    Solutions

    From quantity I,

    Weight of new student=21 * 27 – 20 *28 =7 kg

    From quantity II,

    CP of One kg =14/2 = Rs.7

    SP of one kg=50/5 =Rs.10

    Rs.3 as profit.

    Required answer = 1/3 * 24 =8 kg

     

  • Question 9/10
    1 / -0

    Directions For Questions

    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    a)Quantity I > Quantity II

    b)Quantity I ≥ Quantity II

    c)Quantity II > Quantity I

    d)Quantity II ≥ Quantity I

    e)Quantity I = Quantity II or Relation cannot be established

    ...view full instructions

    Quantity I:A’s age is 120% of B’s age and the sum of the ages of B and C is 72 years and the ratio of the ages of B and C after 8 years is 6:5. What is A’s age after 10 years?

    Quantity II: Average of the ages of A, B and C is 40 years and the ratio of the ages of A, B and C after 4 years is 13:11:9. What is B’s age after 18 years?

    Solutions

    From quantity I,

    After 8 years B + C=72 + 16 =88 years

    11x=88

    X=8

    B’s age after 8 years=8 * 6 =48 years

    Present age of B=48 – 8 =40 years

    A’s age =120/100 * 40 =48 years

    A’s age after 10 years=48 + 10=58 years

    From quantity II,

    A + B + C=120

    After 4 years A + B + C=120 + 12 =132

    B’s age after 4 years=11/33 * 132 =44 years

    B’s age after 18 years=44 + 18 - 4  =58 years

     

  • Question 10/10
    1 / -0

    Directions For Questions

    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    a)Quantity I > Quantity II

    b)Quantity I ≥ Quantity II

    c)Quantity II > Quantity I

    d)Quantity II ≥ Quantity I

    e)Quantity I = Quantity II or Relation cannot be established

    ...view full instructions

    Quantity I: The compound interest accrued on an amount at the end of two years at 10% per annum is Rs.504. What is the sum?

    Quantity II: If the circumference of the circle is 176 cm, then what is the area of the circle?

    Solutions

    From quantity I,

    504=x * (1 + 10/100)2 – x

    504 =21x/100

    X=Rs.2400

    From quantity II,

    2 * 22/7 * r=176

    r=28 cm

    Area of the circle=22/7 * 28 * 28=2464 cm

     

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