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SBI Clerk 2020 Aptitude Test - 17
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SBI Clerk 2020 Aptitude Test - 17
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  • Question 1/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    747.03 ÷ √6890 + √170 * 16.91 – 26.16 * √65 =?

    Solutions

    747.03 ÷ √6890 + √170 * 16.91 – 26.16 * √65 =?

    747 ÷ √6889 + √169 * 17 – 26 * √64 =?

    9 + 221 – 208 =?

    22 =?

     

  • Question 2/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    (13.07)2 + (29.93)2 - (23.314)2 =?

    Solutions

    (13.07)2 + (29.93)2 - (23.314)2 =?

    132 + 302 – 232 =?

    169 + 900 - 529 =?

    540 =?

     

  • Question 3/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    (1710.01 ÷ √3250) – (13.19 * 1.991) =? ÷ √65

    Solutions

    (1710.01 ÷ √3250) – (13.19 * 1.991) =? ÷ √65

    (1710 ÷ √3249 – (13 * 2) =? ÷ √64

    30 – 26 =?/8

    ? = 32

     

  • Question 4/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    29.91% of 580.07 + 21.181 % of 199.91 =? + √2115

    Solutions

    29.91% of 580.07 + 21.181 % of 199.91 =? + √2115

    30/100 * 580 + 21/100 * 200 =? + √2116

    174 + 42 =? + 46

    ? = 170

     

  • Question 5/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    38.91 * 4.99 – 12.04 * √35 + 9.14 * 2.902 =?

    Solutions

    38.91 * 4.99 – 12.04 * √35 + 9.14 * 2.902 =?

    39 * 5 – 12 * √36 + 9 * 3 =?

    195 – 72 + 27 =?

    150 =?

     

  • Question 6/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 + 13x + 22 = 0

    II) y2 + 15y + 26 = 0

    Solutions

    x2 + 13x + 22 = 0

    x2 + 11x + 2x + 22 = 0

    x(x + 11) + 2(x + 11) = 0

    (x + 2)(x + 11) = 0

    x = -2, -11

    y2 + 15y + 26 = 0

    y2 + 13y + 2y + 26 = 0

    y(y + 13) + 2(y + 13) = 0

    (y + 2)(y + 13) = 0

    y = -2, -13

    Relationship between x and y cannot be established.

     

  • Question 7/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) 5x2 - 15x + 10 = 0

    II) y2 - 5y + 6 = 0

    Solutions

    5x2 - 15x + 10 = 0

    5x2 – 10x – 5x + 10 = 0

    5x(x – 2) – 5(x – 2) = 0

    (5x – 5)(x – 2) = 0

    x = 1, 2

    y2 - 5y + 6 = 0

    y2 – 2y – 3y + 6 = 0

    y(y – 2) – 3(y – 2) = 0

    (y – 3)(y – 2) = 0

    y = 3, 2

    x ≤ y

     

  • Question 8/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 – 12x + 32 = 0

    II) y2 – 17y + 72 = 0

    Solutions

    x2 – 12x + 32 = 0

    x2 – 8x – 4x + 32 = 0

    x(x – 8) – 4(x – 8) = 0

    (x – 4)(x – 8) = 0

    x = 4, 8

    y2 – 17y + 72 = 0

    y2 – 8y – 9y + 72 = 0

    y(y – 8) – 9(y – 8) = 0

    (y – 9)(y – 8) = 0

    y = 9, 8

    x ≤ y

     

  • Question 9/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 – 32x + 252 = 0

    II) y2 – 26y + 168 = 0

    Solutions

    x2 – 32x + 252 = 0

    x2 – 14x – 18x + 252 = 0

    x(x – 14) – 18(x – 14) = 0

    (x – 18)(x – 14) = 0

    x = 18, 14

    y2 – 26y + 168 = 0

    y2 – 14y – 12y + 168 = 0

    y(y – 14) – 12(y – 14) = 0

    (y – 12)(y – 14) = 0

    y = 12, 14

    x ≥ y

     

  • Question 10/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 + 13x + 40 = 0

    II) y2 + 19y + 90 = 0

    Solutions

    x2 + 13x + 40 = 0

    x2 + 8x + 5x + 40 = 0

    x(x + 8) + 5(x + 8) = 0

    (x + 5)(x + 8) = 0

    x = -5, -8

    y2 + 19y + 90 = 0

    y2 + 9y + 10y + 90 = 0

    y(y + 9) + 10(y + 9) = 0

    (y + 10)(y + 9) = 0

    y = -10, -9

    x > y

     

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