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LIC AAO & AE 2020 Aptitude Test - 12
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LIC AAO & AE 2020 Aptitude Test - 12
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  • Question 1/10
    1 / -0

    Directions For Questions

    The following questions are accompanied by three statements I and II. You have to determine which statement is/are sufficient to answer the question.

    a) Only I

    b) Only II

    c )Either I or II sufficient

    d) All I and II necessary to the answer the question

    e) The question can’t be answered even with all I and II

    ...view full instructions


    Find the sum?

    Statement I: The amount becomes Rs.3600 in one year at simple interest.

    Statement II: The amount becomes Rs.5400 in 2 years at compound interest.

    Solutions

    From Statement I,

    3600 - x=x * 1 * R/100

    3600=x + x * 1 * R/100

    3600=x( 1+ R/100)

    So, Statement I alone is not sufficient to the answer the question.

    From statement II,

    5400=x* (1 + R/100) 2

     So, Statement II alone is not sufficient to the answer the question.

    From I and II

    x * (1 + R/100)2 / x * (1+ R/100)=5400/3600

    1 + R/100 =3/2

    R=50%

    3600=x(1 + 50/100)

    X=2400

     

  • Question 2/10
    1 / -0

    Directions For Questions

    The following questions are accompanied by three statements I and II. You have to determine which statement is/are sufficient to answer the question.

    a) Only I

    b) Only II

    c )Either I or II sufficient

    d) All I and II necessary to the answer the question

    e) The question can’t be answered even with all I and II

    ...view full instructions


    Find the speed of boat in still water?

    Statement I: The boat goes downstream from one point to another in 6 hours.

    Statement II: The boat goes upstream from one point to another in 14 hours.

    Solutions

    From statement I,

    Distance is not given.

    So, Statement I alone is not sufficient to the answer the question.

    From statement II,

    Distance is not given.

    So, Statement II alone is not sufficient to the answer the question.

     

  • Question 3/10
    1 / -0

    Directions For Questions

    The following questions are accompanied by three statements I and II. You have to determine which statement is/are sufficient to answer the question.

    a) Only I

    b) Only II

    c )Either I or II sufficient

    d) All I and II necessary to the answer the question

    e) The question can’t be answered even with all I and II

    ...view full instructions


    What is value of A?

    Statement I: A is twice of B and half of C.

    Statement II: Average of A, B and C is 56.

    Solutions

    From statement I,

    B=x

    A=2x

    C=4x

    So, Statement I alone is not sufficient to the answer the question.

    From statement II,

    A + B + C=168

    So, Statement II alone is not sufficient to the answer the question.

    From I and II,

    2x + x + 4x =168

    7x=168

    X=24

    A=2 * 24=48

     

  • Question 4/10
    1 / -0

    Directions For Questions

    The following questions are accompanied by three statements I and II. You have to determine which statement is/are sufficient to answer the question.

    a) Only I

    b) Only II

    c )Either I or II sufficient

    d) All I and II necessary to the answer the question

    e) The question can’t be answered even with all I and II

    ...view full instructions


    What is the area of the square?

    Statement I: If the ratio of the length of rectangle to side of the square is 3:2 and the perimeter of the rectangle is 60 cm.

    Statement II: If the side of the square increased by 10 cm and the area of the rectangle is increased by 20%.

    Solutions

    From Statement I,

    2(l + B)=60 cm

    So, Statement I alone is not sufficient to the answer the question.

    From statement II,

    Side of the square=x + 10

    So, Statement II alone is not sufficient to the answer the question.

     

  • Question 5/10
    1 / -0

    Directions For Questions

    The following questions are accompanied by three statements I and II. You have to determine which statement is/are sufficient to answer the question.

    a) Only I

    b) Only II

    c )Either I or II sufficient

    d) All I and II necessary to the answer the question

    e) The question can’t be answered even with all I and II

    ...view full instructions


    What is the length of train?

    Statement I: A train crosses the 480 m bridge in 54 seconds at the speed of 90 kmph.

    Statement II: If the train crosses the car running in opposite direction at the speed of 60 kmph in 18 seconds?

    Solutions

    From Statement I,

    480 + x=90 * 5/18 * 54

    X=870m

    So, Statement I alone is sufficient to the answer the question.

    From statement II,

    Speed of train is not given.

    So, Statement II alone is not sufficient to the answer the question.

     

  • Question 6/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    A Jar contains a mixture of Milk and Water in the ratio of 3:2. Jar contains 18 liter of milk in initially. When (S) liter of the mixture taken out and (S) liter of water is poured into Jar, the ratio becomes 2:3. The milkman has 70 liter of the mixture of milk and water in the ratio of 7:3. The milkman gave (S) liters of mixture to customer and then he added (T) liter of pure milk and (T) liter water to the remaining mixture. As a final result the ratio of the milk and water in the ratio of 2:1. A vessel contains (V) liter of mixture of milk and water in the ratio of 7:5 and 9 liter of mixture taken out and added 9 liter of water, then the ratio of milk and water becomes 7:9. A bag contains (50% of S) red balls, T Yellow balls and 3 green balls. If two balls are picked at random, then the probability that either both are red or both are green color is (U).The edgeof the cube is (V) and the surface area of the cube is (W).

    ...view full instructions


    Find the in the place of (S)

    Solutions

    Milk in the mixture of Sliter=3/5 * S=3S/5 liter

    Water=2/5 * S=2S/5 liter

    (18 - 3S/5) / (12 - 2S/5 + S)=2/3

    (90 - 3S) / (60 + 3S)=2/3

    270 - 9S = 120 + 6S

    15S=150

    S=10 liter

    Milk in 70 liter=7/10 * 70= 49 liter

    Water in 70 liter=3/10 *70=21 liter

    Milk in 10 liter=7/10 * 10=7 liter

    Water in 10 liter=3/10 *10=3 liter

    (49 – 7 + T) / (21 – 3 +T) = 2 /1

    42 + T=36 + 2T

    T=6 liters

    (7x – 7/12 * 9) / (5x – 5/12 * 9 +9) = 7 /9

    (28x – 21) / (20x + 21) =7 / 9

    252x – 189 = 140x + 147

    X=3

    V=12x=12 * 3= 36 liter

    V = 36 liter

    Red=10 * 50/100 =5

    Yellow=6

    Green=3

    Required probability (U)=5C2 + 3C2 / 14C2

    (U) =10 + 3 / 91=1/7

    U = 1/7

    Surface area of the cube (W) =6 * 36 * 36=7776 cm2

    W = 7776 cm2

     

  • Question 7/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    A Jar contains a mixture of Milk and Water in the ratio of 3:2. Jar contains 18 liter of milk in initially. When (S) liter of the mixture taken out and (S) liter of water is poured into Jar, the ratio becomes 2:3. The milkman has 70 liter of the mixture of milk and water in the ratio of 7:3. The milkman gave (S) liters of mixture to customer and then he added (T) liter of pure milk and (T) liter water to the remaining mixture. As a final result the ratio of the milk and water in the ratio of 2:1. A vessel contains (V) liter of mixture of milk and water in the ratio of 7:5 and 9 liter of mixture taken out and added 9 liter of water, then the ratio of milk and water becomes 7:9. A bag contains (50% of S) red balls, T Yellow balls and 3 green balls. If two balls are picked at random, then the probability that either both are red or both are green color is (U).The edgeof the cube is (V) and the surface area of the cube is (W).

    ...view full instructions


    Find the in the place of (T)

    Solutions

    Milk in the mixture of Sliter=3/5 * S=3S/5 liter

    Water=2/5 * S=2S/5 liter

    (18 - 3S/5) / (12 - 2S/5 + S)=2/3

    (90 - 3S) / (60 + 3S)=2/3

    270 - 9S = 120 + 6S

    15S=150

    S=10 liter

    Milk in 70 liter=7/10 * 70= 49 liter

    Water in 70 liter=3/10 *70=21 liter

    Milk in 10 liter=7/10 * 10=7 liter

    Water in 10 liter=3/7 *10=3 liter

    (49 – 7 + T) / (21 – 3 +T) = 2 /1

    42 + T=36 + 2T

    T=6 liters

    (7x – 7/12 * 9) / (5x – 5/12 * 9 +9) = 7 /9

    (28x – 21) / (20x + 21) =7 / 9

    252x – 189 = 140x + 147

    X=3

    V=12x=12 * 3= 36 liter

    V = 36 liter

    Red=10 * 50/100 =5

    Yellow=6

    Green=3

    Required probability (U)=5C2 + 3C2 / 14C2

    (U) =10 + 3 / 91=1/7

    U = 1/7

    Surface area of the cube (W) =6 * 36 * 36=7776 cm2

    W = 7776 cm2

     

  • Question 8/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    A Jar contains a mixture of Milk and Water in the ratio of 3:2. Jar contains 18 liter of milk in initially. When (S) liter of the mixture taken out and (S) liter of water is poured into Jar, the ratio becomes 2:3. The milkman has 70 liter of the mixture of milk and water in the ratio of 7:3. The milkman gave (S) liters of mixture to customer and then he added (T) liter of pure milk and (T) liter water to the remaining mixture. As a final result the ratio of the milk and water in the ratio of 2:1. A vessel contains (V) liter of mixture of milk and water in the ratio of 7:5 and 9 liter of mixture taken out and added 9 liter of water, then the ratio of milk and water becomes 7:9. A bag contains (50% of S) red balls, T Yellow balls and 3 green balls. If two balls are picked at random, then the probability that either both are red or both are green color is (U).The edgeof the cube is (V) and the surface area of the cube is (W).

    ...view full instructions


    Find the in the place of (U)

    Solutions

    Milk in the mixture of Sliter=3/5 * S=3S/5 liter

    Water=2/5 * S=2S/5 liter

    (18 - 3S/5) / (12 - 2S/5 + S)=2/3

    (90 - 3S) / (60 + 3S)=2/3

    270 - 9S = 120 + 6S

    15S=150

    S=10 liter

    Milk in 70 liter=7/10 * 70= 49 liter

    Water in 70 liter=3/10 *70=21 liter

    Milk in 10 liter=7/10 * 10=7 liter

    Water in 10 liter=3/7 *10=3 liter

    (49 – 7 + T) / (21 – 3 +T) = 2 /1

    42 + T=36 + 2T

    T=6 liters

    (7x – 7/12 * 9) / (5x – 5/12 * 9 +9) = 7 /9

    (28x – 21) / (20x + 21) =7 / 9

    252x – 189 = 140x + 147

    X=3

    V=12x=12 * 3= 36 liter

    V = 36 liter

    Red=10 * 50/100 =5

    Yellow=6

    Green=3

    Required probability (U)=5C2 + 3C2 / 14C2

    (U) =10 + 3 / 91=1/7

    U = 1/7

    Surface area of the cube (W) =6 * 36 * 36=7776 cm2

    W = 7776 cm2

     

  • Question 9/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    A Jar contains a mixture of Milk and Water in the ratio of 3:2. Jar contains 18 liter of milk in initially. When (S) liter of the mixture taken out and (S) liter of water is poured into Jar, the ratio becomes 2:3. The milkman has 70 liter of the mixture of milk and water in the ratio of 7:3. The milkman gave (S) liters of mixture to customer and then he added (T) liter of pure milk and (T) liter water to the remaining mixture. As a final result the ratio of the milk and water in the ratio of 2:1. A vessel contains (V) liter of mixture of milk and water in the ratio of 7:5 and 9 liter of mixture taken out and added 9 liter of water, then the ratio of milk and water becomes 7:9. A bag contains (50% of S) red balls, T Yellow balls and 3 green balls. If two balls are picked at random, then the probability that either both are red or both are green color is (U).The edgeof the cube is (V) and the surface area of the cube is (W).

    ...view full instructions


    Find the in the place of (V)

    Solutions

    Milk in the mixture of Sliter=3/5 * S=3S/5 liter

    Water=2/5 * S=2S/5 liter

    (18 - 3S/5) / (12 - 2S/5 + S)=2/3

    (90 - 3S) / (60 + 3S)=2/3

    270 - 9S = 120 + 6S

    15S=150

    S=10 liter

    Milk in 70 liter=7/10 * 70= 49 liter

    Water in 70 liter=3/10 *70=21 liter

    Milk in 10 liter=7/10 * 10=7 liter

    Water in 10 liter=3/7 *10=3 liter

    (49 – 7 + T) / (21 – 3 +T) = 2 /1

    42 + T=36 + 2T

    T=6 liters

    (7x – 7/12 * 9) / (5x – 5/12 * 9 +9) = 7 /9

    (28x – 21) / (20x + 21) =7 / 9

    252x – 189 = 140x + 147

    X=3

    V=12x=12 * 3= 36 liter

    V = 36 liter

    Red=10 * 50/100 =5

    Yellow=6

    Green=3

    Required probability (U)=5C2 + 3C2 / 14C2

    (U) =10 + 3 / 91=1/7

    U = 1/7

    Surface area of the cube (W) =6 * 36 * 36=7776 cm2

    W = 7776 cm2

     

  • Question 10/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    A Jar contains a mixture of Milk and Water in the ratio of 3:2. Jar contains 18 liter of milk in initially. When (S) liter of the mixture taken out and (S) liter of water is poured into Jar, the ratio becomes 2:3. The milkman has 70 liter of the mixture of milk and water in the ratio of 7:3. The milkman gave (S) liters of mixture to customer and then he added (T) liter of pure milk and (T) liter water to the remaining mixture. As a final result the ratio of the milk and water in the ratio of 2:1. A vessel contains (V) liter of mixture of milk and water in the ratio of 7:5 and 9 liter of mixture taken out and added 9 liter of water, then the ratio of milk and water becomes 7:9. A bag contains (50% of S) red balls, T Yellow balls and 3 green balls. If two balls are picked at random, then the probability that either both are red or both are green color is (U).The edgeof the cube is (V) and the surface area of the cube is (W).

    ...view full instructions


    Find the in the place of (W)

    Solutions

    Milk in the mixture of Sliter=3/5 * S=3S/5 liter

    Water=2/5 * S=2S/5 liter

    (18 - 3S/5) / (12 - 2S/5 + S)=2/3

    (90 - 3S) / (60 + 3S)=2/3

    270 - 9S = 120 + 6S

    15S=150

    S=10 liter

    Milk in 70 liter=7/10 * 70= 49 liter

    Water in 70 liter=3/10 *70=21 liter

    Milk in 10 liter=7/10 * 10=7 liter

    Water in 10 liter=3/7 *10=3 liter

    (49 – 7 + T) / (21 – 3 +T) = 2 /1

    42 + T=36 + 2T

    T=6 liters

    (7x – 7/12 * 9) / (5x – 5/12 * 9 +9) = 7 /9

    (28x – 21) / (20x + 21) =7 / 9

    252x – 189 = 140x + 147

    X=3

    V=12x=12 * 3= 36 liter

    V = 36 liter

    Red=10 * 50/100 =5

    Yellow=6

    Green=3

    Required probability (U)=5C2 + 3C2 / 14C2

    (U) =10 + 3 / 91=1/7

    U = 1/7

    Surface area of the cube (W) =6 * 36 * 36=7776 cm2

    W = 7776 cm2

     

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