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LIC AAO & AE 2020 Aptitude Test - 13
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LIC AAO & AE 2020 Aptitude Test - 13
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  • Question 1/10
    1 / -0

    What value should come in place of question mark in the following questions?

     35 * 18 – 19 * 21 + ? =42 *8

    Solutions

    630 – 399 + ? =336

    ?=105

     

  • Question 2/10
    1 / -0

    What value should come in place of question mark in the following questions?

     20% of 145 – 13% of 300 + √784 * 6 =?

    Solutions

    29 – 39 + 168 =?

    ?=158

     

  • Question 3/10
    1 / -0

    What value should come in place of question mark in the following questions?

    212 +? – 150% of 124 + 18% of 350 = 129

    Solutions

    212 + ? -186 + 63 = 129

    ?=40

     

  • Question 4/10
    1 / -0

    What value should come in place of question mark in the following questions?

    304 ÷ √256 + 23 * 33 + 60% of 40 = ? * 401

    Solutions

    19 + 759 + 24 =? * 401

    ?=2

     

  • Question 5/10
    1 / -0

    What value should come in place of question mark in the following questions?

    1224 ÷ 17 + 81 * 4 – 126 = ? * 9

    Solutions

    72 + 324 – 126 =? * 9

    ?=30

     

  • Question 6/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x>y

    b) If x≥y

    c) If x<y

    d) If x≤y

    e) If x=y or the relation cannot be established.

    ...view full instructions

    I) x2 + 29x + 208 =0

    II)y2 + 18y + 45 =0

    Solutions

    x2 + 29x + 208 =0

    x2 + 13x + 16x + 208=0

    x(x + 13) + 16( x + 13)=0

    (x + 16) (x + 13)=0

    x=-16, -13

    y2 + 18y + 45 =0

    y2 + 15y + 3y + 45 =0

    y(y + 15) + 3(y +15)=0

    (y + 3)(y + 15)=0

    y=-3, -15

     

  • Question 7/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x>y

    b) If x≥y

    c) If x<y

    d) If x≤y

    e) If x=y or the relation cannot be established.

    ...view full instructions

    I) x2 - 2x – 255 =0

    II) y2 + 24y + 119=0

    Solutions

    x2 - 2x – 255 =0

    x2 – 17x + 15x – 255=0

    x(x – 17) + 15(x – 17)=0

    (x + 15) (x – 17)=0

    x=-15, 17

    y2 + 24y + 119=0

    y2 + 17y + 7y +119=0

    y(y + 17) + 7(y + 17)=0

    (y + 7) (y + 17)=0

    y=-7, -17

     

  • Question 8/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x>y

    b) If x≥y

    c) If x<y

    d) If x≤y

    e) If x=y or the relation cannot be established.

    ...view full instructions

    I) 2x2 + 28x + 66=0

    II) 3y2 + 25y + 38=0

    Solutions

    2x2 + 28x + 66=0

    2x2 + 22x + 6x + 66=0

    2x(x + 11) + 6(x + 11)=0

    (2x + 6) (x + 11)=0

    x=-3, -11

    3y2 + 25y + 38=0

    3y2 + 19y + 6y + 38 =0

    3y (y + 2) + 19(y + 2)=0

    (3y + 19)(y + 2)=0

    y=-2, -19/3

     

  • Question 9/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x>y

    b) If x≥y

    c) If x<y

    d) If x≤y

    e) If x=y or the relation cannot be established.

    ...view full instructions

    I) x2 – 23x + 132=0

    II)y2 – 31y + 228=0

    Solutions

    x2 – 23x + 132=0

    x2 –11x – 12x + 132=0

    x(x – 11) - 12(x – 11)=0

    (x – 12)(x – 11)=0

    x=12, 11

    y2 – 31y + 228=0

    y2 –12y – 19y + 228=0

    y(y - 12) – 19(y – 12)=0

    (y – 19) (y – 12)=0

    y=19, 12

     

  • Question 10/10
    1 / -0

    Directions For Questions

    In the following questions, two equations I and II are given. You have to solve both equations and give answer as,

    a) If x>y

    b) If x≥y

    c) If x<y

    d) If x≤y

    e) If x=y or the relation cannot be established.

    ...view full instructions

    I) x2 + 10x – 75=0

    II) y2 + 12y + 35=0

    Solutions

    x2 + 10x – 75=0

    x2 + 15x – 5x – 75=0

    x(x + 15) – 5(x + 15)=0

    (x – 5) (x + 15)=0

    x=5, -15

    y2 + 12y + 35=0

    y2 + 5y + 7y + 35=0

    y(y + 5) + 7(y + 5)=0

    (y + 7) (y + 5)=0

    y=-7, -5

     

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