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LIC AAO & AE 2020 Aptitude Test - 17
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LIC AAO & AE 2020 Aptitude Test - 17
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  • Question 1/10
    1 / -0

    The ratio of the present ages of A and B is 5:6 and after 10 years the ratio becomes 7:8. C’s age is 120% of the ages of A, what is C’s age after 20 years?

    Solutions

    (5x + 10) / (6x +10) = 7/8

    40x + 80=42x + 70

    2x=10

    X=5

    A’s present age = 5 * 5 = 25 years

    C’s present age=25 * 120/100=30 years

    After 20 years C’s age=30 + 20=50 years.

     

  • Question 2/10
    1 / -0

    10 men and 12 women do the piece of work in 7 days and 8 men and 16 women can do the piece of work in 6 days. In how many days can 22 men and 12 women do the same work?

    Solutions

    (10m + 12w) * 7=(8m + 16w) * 6

    70m + 84w=48m + 96w

    22m=12w

    (10m + 22m)*7=(22m + 22m) * ?

    32m * 7=44m * ?

    ?=56/11=5(1/11) days

     

  • Question 3/10
    1 / -0

    Sonu invested his amount in two different schemes A and B in the ratio of 3:2. Scheme A and B offer the simple interest at the rate of 10% and 15% respectively. At the end of 4 years he received the total interest by both schemes is half of his total investment of both schemes, what is the amount invested by scheme A?

    Solutions

    The principle amount is not given in the question. Hence, the answer cannot be determined.

     

  • Question 4/10
    1 / -0

    If the ratio of the radius to height of the cylinder is 7:8 and the volume of the cylinder is 1232 cm3. Radius of the cylinder is equal to the radius of sphere, what is the surface area of sphere?

    Solutions

    1232=22/7 * 7x *7x * 8x

    X=1 cm

    Radius of the cylinder =7 * 1=7 cm

    Surface area of the sphere=4 * 22/7 * 7 * 7=616 cm2

     

  • Question 5/10
    1 / -0

    The ratio of the monthly income of A and B is 6:7 and the expenditure of A and B is 10:13. If both are saved Rs.8000 per month, what is the annual income of B?

    Solutions

    (6x – 8000) / (7x – 8000) = 10/13

    70x – 80000 = 78x – 104000

    8x=24000

    X=Rs.3000

    B’s monthly income = 7 * 3000=21000

    Annual income of B = 21000 * 12=252000

     

  • Question 6/10
    1 / -0

    If the boat can travel 90 km upstream and downstream in 12 hours and downstream speed is 50% more than that of speed of boat in still water, then what is the speed of stream?

    Solutions

    Let speed of boat in still water=x

    Stream speed=y

    Downstream speed=x * 150/100=3x/2

    X + y = 3x/2

    Y = x/2

    X=2y

    Downstream Speed = 3 * 2y/2 = 3y

    Upstream speed = x-y = 2y-y = y

    90/3y + 90/y =12

    120/y=12

    Y= 10 kmph

     

  • Question 7/10
    1 / -0

    A, B and C started the business with the investment of Rs.x, Rs.(x + 1000) and Rs.(x – 2000) respectively. After 6 months A withdrew 25% of his initial investment and at the end of one year the total profit and B’s share is Rs.6500 and Rs.2800 respectively. What is the value of x?

    Solutions

    Profit ratio=(x * 6 + x * 75/100 *6) : (x +1000) *12: (x – 2000) * 12

    =(6x + 9x/2): 12x +12000: 12x – 24000

    =10.5x: 12x + 12000: 12x – 24000

    (12x + 12000) / (34.5x -12000) =2800/6500

    966x – 336000=780x + 780000

    186x=116000

    X=6000

     

  • Question 8/10
    1 / -0

    A Jar contains the mixture of milk and water in the ratio of 3:1. 20 liter of the mixture is taken out from the Jar and replaced with same amount of water. Now the ratio of milk and water becomes 1:1, find the quantity of the water in the initial mixture?

    Solutions

    Milk in 20 liter=3/4 * 20=15 liters

    Water in 20 liters=1/4 * 20=5 liters

    3x - 15/x – 5 + 20=1/1

    3x -15=x + 15

    2x=30

    X=15 liters

     

  • Question 9/10
    1 / -0

    The difference between the simple and compound interest for 2 years is Rs.12 at the rate of 10%. The same amount deposited to the bank offer the simple interest at the rate of 20% for 8 years, what is the interest earned by after 8 years?

    Solutions

    The difference between the simple and compound interest for 2 years = Pr2/1002

    12= P *(10 * 10) / (100 *100)

    P=1200

    SI=1200 * 20 * 8/100=1920

     

  • Question 10/10
    1 / -0

    Two vessels A and B contain milk and water in the mixture in the ratio of 4:3 and 2:3 respectively. If both vessels are mixed in vessel C, then what is the ratio of milk and water in final mixture?

    Solutions

    Millk : Water=(4/7 + 2/5) : (3/7 + 3/5)

    =(20 + 14)/35 : (15 + 21)/35

    =34 : 26=17:18

     

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