Please wait...

IBPS PO 2020 Aptitude Test - 3
Menu grid icon
Result Result point icon
IBPS PO 2020 Aptitude Test - 3
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    1 / -0

    Two containers, A and B have certain quantities of the mixture in them. In container A, three liquids X, Y and Z are mixed in the ratio of 5 : 4 : 3 respectively and in container B two liquids Y and Z are mixed in the ratio of 16 : 15 respectively. Mixtures from both containers A and B are poured into an empty container C. The ratio of the quantities of liquids X, Y and Z in container C becomes 25 : 68 : 60 respectively. Quantity of mixture in container B is how much percent less or more than the quantity of mixture in container A?

    Solutions

    Let in A, quantity of liquid X, Y and Z is ‘5x’, ‘4x’ and ‘3x’ litres respectively

    And in B, quantity of liquid Y and Z is ‘16y’ and ‘15y’ respectively

    According to the question:

    So, x = 5 and y = 3

    Quantity in container A = 12x = 60 litres

    Quantity in container B = 31y = 93 litres

     

  • Question 2/10
    1 / -0

    Narendra rana obtained equal marks in Maths and Science. The ratio of marks in Science and Economics is 2 : 3 and the ratio of marks in Math and Hindi is 1 : 5. If he has scored an aggregate of 51% marks. The maximum marks in each subject is same. In how many subjects did he score equal to or greater than 60% marks?

    Solutions

    Ratio of marks in Math to Science= 1 : 1
    Ratio of marks in Science to Economics = 2 : 3
    Ratio of marks in Math to Hindi = 1 : 5
    Ratio of marks in Math : Science : Economics = 2 : 2 : 3
    Now ratio of marks in Math : Science : Economics : Hindi = 2 : 2 : 3 : 10
    Let the marks in Math, Science, Economics and Hindi be 2x, 2x, 3x and 9x ….respectively
    (2x + 2x + 3x + 10x)/4 = 51
    17x / 4 = 51
    x = 12
    Marks in Math = 2x = 24
    Marks in Science = 2x = 24
    Marks in Economics = 3x = 36
    Marks in Hindi = 10x = 120
    ∴ in one subjects he scored 60% or above

     

  • Question 3/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions given below.

    The given table shows the total number of students appeared in board examination and ratio of passed to failed students of different states in different years.

    ...view full instructions

    Find the ratio of passed student of state A in 2001 to failed students of state C in year 2004.

    Solutions

    Passed students of state A in 2001=5215 × 4/7=2980

    Failed students od state C in 2004=8500 × 4/10=3400

    Required ratio=2980:3400=149:170.

     

  • Question 4/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions given below.

    The given table shows the total number of students appeared in board examination and ratio of passed to failed students of different states in different years.

    ...view full instructions

    The total students passed in state A and B in the year 2004 is approximately what percent more than the students passed in state B and C in year 2001?

    Solutions

    Total number of students passed from states A and B together in 2004 = 4634 + 4585 = 9219

    Total number of students passed from states B and C together in 2001 = 2958 + 4625 =7583

    Hence, the required percentage =[(9219 – 7583)/7583] × 100 ≈ 22%.

     

  • Question 5/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions given below.

    The given table shows the total number of students appeared in board examination and ratio of passed to failed students of different states in different years.

    ...view full instructions

    In the state B, which year had the 2nd highest percentage of students passed over the students appeared?

    Solutions

    2000=3364/5046 × 100=66.66%

    2001=2958/6902 × 100=42.85%

    2002=3995/7191 × 100=55.55%

    2003=3020/8305 × 100=36.36%

    2004=4585/7860 × 100=58.33%

    2005=3465/6545 × 100=52.94%

    2nd highest percentage of passed student=2004

     

  • Question 6/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions given below.

    The given table shows the total number of students appeared in board examination and ratio of passed to failed students of different states in different years.

    ...view full instructions

    Find the average of fail students in year 2000,2003 and 2004 of state C.

    Solutions

    2000=7319 × 6/13=3378

    2003=8232 × 7/12=4802

    2005=8500 × 4/10=3400

    Average=(3378+4802+3400)/3

    11580/3=3860

     

  • Question 7/10
    1 / -0

    10 women can complete a work in 9 days and 10 children takes 18 days to complete the work. How many days will 5 women and 10 children take to complete the work?

    Solutions

     

  • Question 8/10
    1 / -0

    In the month of January, Suresh spent 55% of his monthly salary on paying bill and rent. Out of the remaining salary, he invested 50% in PPF and the remaining he deposited in bank. He deposited Rs. 21,600 in the bank. What was his salary ?

    Solutions

    Let the salary of Suresh in the month of February = x

     

  • Question 9/10
    1 / -0

    Time taken by a boat to covers 256km in upstream is 300% more than the time taken by boat to cover same distance in downstream. Total time, taken by boat for entire journey is 20 hours. Find the speed of stream.

    Solutions

    Let the time taken to cover downstream be x and time taken by boat in upstream will be 4x

    Sum of the time taken by boat in downstream and in upstream = 20 hours

    x + 4x = 20

    x = 4

    So, time taken by boat in upstream = 4 × 4 = 16 hours

    Time taken by boat in downstream = 4 hours

    A.T.Q,

    Let the speed of boat be ‘b km/h’ and speed of stream be ‘c km/h’

    In upstream,

    256/b-c = 16

    b – c = 16 ----- (i)

    In downstream,

    256/b+c = 4

    b + c = 64 --------- (ii)

    On solving (i) and (ii), we get

    b = 40 km/h and c = 24 km/h

     

  • Question 10/10
    1 / -0

    8 years hence, the ratio of age of Anmol and Ayushi is 8: 7. 4 years ago, Anmol's age is equal to the age of Ayushi 4 years hence. Find the sum of the ages of both 6 years ago.

    Solutions

    A.T.Q,

    56 + 7 Anmol = 64 + 8 Ayushi

    7 Anmol – 8 Ayushi = 8 -------- (I)

    Anmol – 4 = Ayushi + 4

    Anmol – Ayushi = 8 ---------- (II)

    On equating eq. (I) and eq. (II), we get,

    7 Anmol – 8 Ayushi = Anmol – Ayushi

    6 Anmol = 7 Ayushi

    Anmol = 7/6 Ayushi

    On putting this in eq. (II), we get,

    Ayushi = 48 years

    Anmol = 56 years

    Required answer = 48 + 56 – 12

    = 92

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now