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AFCAT Test 14
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AFCAT Test 14
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  • Question 1/5
    1 / -0.33

    AnGaD = DaGnA . Then what is PrItHvIrAj called by?
    Solutions

    Here, the first letter is written in Capital, and next letter in small, and so on, in both the normal and reversed orders. So, answer for next part is option (b).

  • Question 2/5
    1 / -0.33

    Understand the logic behind it and answer accordingly:

    b1.png

    Solutions

    The sum of lower semi-circle:

    The sum of upper semi circle should be 30, then-

    This shows that value 15 can be the only value to verify the equation.

    Hence, answer is option (b).

  • Question 3/5
    1 / -0.33

    A man can walk 25 Km and 85 Km in integral numbers of minutes then what is the greatest possible speed at which he can walk?
    Solutions

    The concept behind this problem is very simple – as we have to find out the rat e of walking and the rate is in such a way when divide any one of these km then the result will be a integer.
    So, we have to find out the HCF of these two numbers-
    And the HCF of these number is 5 , so our answer is 5 Km/min

  • Question 4/5
    1 / -0.33

    If each side of a rectangle is decreased by 11%, then its area will decrease by:
    Solutions

    Let the length of the rectangle be x and the breadth be y.

    Then the area of the rectangle = xy

    Now, decreased length = x – (x) × 11% = x – 0.11x = 0.89x

    And decreased breadth = y – (y) × 11% = y – 0.11y = 0.89y

    Revised area of the rectangle = (0.89x) × (0.89y) = 0.7921xy

    Hence, Change in area =

  • Question 5/5
    1 / -0.33

    A man brought some chocolates at 3 for a rupee. How many for a rupee should he sell to make a profit 50%?
    Solutions

    C.P of 3 chocolates = Re. 1
    S.P of 3 chocolates = 150% of Re.1 = 

    For Rs , number of chocolates sold =3
    for Re.1, number of chocolates sold = 

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