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Simplification of (cosecθ-cotθ)2
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(cosecθ-cotθ)2
If sec4A = cosec(A - 10°) and 4A is acute then A is equal to:
Given, sec4A = cosec(A - 10°) We know that secθ = cosec(90° - θ) where θ is an acute angle. Thus, cosec(90° - 4A) = cosec(A - 10°)
On comparing both sides:
90° - 4A = A - 10°
⇒ 5A = 100°
⇒ A = 20°
If cosecθ + cotθ = p then cosθ = ?
cosecθ+cotθ=p
If sin(A + B) = sinAcosB + cosAsinB then fine that value of sin75
Let A=45 and B=30
sin(A+B)=sinAcosB+cosAsinB
sin(75)=sin45cos30+cos45sin30
find the value of 3(x2-1/ x2) if cosecθ=3x and cotθ=3/x
If sinθ = x the value of cotθ
Cot θ=cosθ/sinθ
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