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Aptitude Test 228
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Aptitude Test 228
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  • Question 1/10
    1 / -0.33

    A container contains a mixture of two liquids A and B in the ratio 3: 2. When 5 litres of mixture are drawn off and the container is filled with B, the ratio of A and B becomes 1 : 1. How many litres of liquid A was contained by the container initially?

    Solutions

     

  • Question 2/10
    1 / -0.33

    The average of 11 results is 50. The average of the 6 results is 49 and that of the last 6 results is 52. What is the 6th result?

    Solutions

    6 \text { th result }=6 \times 49+6 \times 52-11 \times 50=56

     

  • Question 3/10
    1 / -0.33

    When F is written as a Traction in lowest terms, the denominator exceeds the numerator by:

    Solutions

     

  • Question 4/10
    1 / -0.33

    A man bought a watch at 25% discount on the original price. He got Rs.40 more than the original price by selling it at 140% of the price at which he bought. The price of buying the watch was:

    Solutions

    Let original price be Rs. x C⋅P⋅=RS⋅0.75

    According to question 0.75× 140/100 = x+40

    ⇒1.05x = x+40

    ⇒ x=800

    The price of buying the watch 

    =800×0.75 

    =Rs.600

    Hence, the correct option is (B).

     

  • Question 5/10
    1 / -0.33

    The LCM and HCF of 2 numbers are 168 and 6 respectively. If one of the numbers is 24, find the other.

    Solutions

    We know that

    Products of 2 numbers = products if their LCM,HCF 

    24×x = 168×6

    Second number = 42

     

  • Question 6/10
    1 / -0.33

    The present age of Sonu is 12 years more than twice the present age of Monu. Three years hence, the average age of Sonu and Monu will be 27 years. Find the ratio of the present age of Monu to that of Sonu.

    Solutions

    Let the present age of Monu be x years.

    Present age of Sonu = (2x+12) years

    According to the question,

    Hence, the correct option is (A).

     

  • Question 7/10
    1 / -0.33

    The area of a rectangle is 42sq.cm and its length is 7cm. Find its perimeter.

    Solutions

    Area of rectangle = L x B

    42 = 7 x B

    B = 6cm

    perimeter = 2(L+B) = 2(7+6) = 26cm

     

  • Question 8/10
    1 / -0.33

    A triangle has a perimeter of 200. If two of its sides are equal and the third side is 20 more than the equal sides, what is the length of the third side?

    Solutions

    Let 1st and 2nd side =x

    Then 3rd side = x+20

    Perimeter = x+x+x+20=3x+20=200

    X=60

    Third side = x+20=80

     

  • Question 9/10
    1 / -0.33

    The sides of a triangle are in the ratio of 7:9:12. The difference between the lengths of the largest and the smallest side is 15 cm. The length of the largest side is-

    Solutions

    Given-

    The sides of a triangle are in the ratio of 7:9:12.

    Let the sides be 7k, 9k, 12k.

    The difference between the lengths of the largest and the smallest side is 15 cm.

    ⇒12k-7k=15 cm

    ⇒5k=15 cm

    ⇒k=3 cm

    Length of the largest side =12k

    =(12×3) cm

    =36 cm

    Hence, the correct option is (A).

     

  • Question 10/10
    1 / -0.33

    The median of the following numbers arranged in ascending order is 2.5, if so find x?

    0, 0, 1, 1, 2, 2, x, 3, 3, 4, 5, 7

    Solutions

    Given observations in ascending order are: 0,0,1,1,2,2,x,3,3,4,5,7 Median 

     

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