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Correct Answer is option B
Formula used:
1. if r = n - r
2.
Calculation:
Given C(28, 2r) = C(28, 2r – 4)
So, 2r = 28 – 2r + 4
r = 8
Correct Answer is option C
Given:
If
Then
From above []
First of all
So,
Since, then or
Cofactor of element is defined as
Where is determinant obtained by the deleting row and column from the given matrix.
Element 4 in 2nd row and 1st column so ,
………[]
,
Now,
Given that,
α and β are the roots of the equation ,
let ,
then,
Now, put value of α in eqn.
Now, p is replaced by x, and we get equation
Correct Answer is option D
Let be the terms of G.P
Given,
Correct Answer is option A
Total number of subsets of the first is while total number of subsets of the second is
Hence compare the terms
Hence,
Let be 100 observations.
Standard deviation =
Then,
Variance =
We have,
Let
By using the formula
Here
Now
For differentiate wrt , firstly differentiate wrt and wrt
And,
Therefore then is continuous at x=4.
When , we have
The area enclosed by and the coordinate axes is shaded in figure.
Let be the required area. Then,
We know that the coordinates of the image of a point in the plane are given by
Let be the image of the point in the plane . Then,
, ,
Hence, the image has the coordinates .
Given planes : x+y+z=1
:2x+3y+4z =7
So , equation of plane passing through intersection of planes P1 and P2 is
⇒ x+y+z-1+k(2x+3y+4z-7)=0
⇒ x+y+z-1+2kx+3ky+4kz-7k=0
⇒ x(1+2k) +y( 1+3k) + z ( 1+4k) -1 -7k = 0\
this is perpendicular to x-5y+3z = 5
⇒ x-5y+3z-5=0
So
⇒ 1(1+2k) – 5( 1+3k ) + 3 (1+4k )=0
⇒ 1+2k-5-15k+3+12k = 0
⇒ k-1 = 0
⇒ k=-1
equations of plane is
⇒ x+y+z-1-1(2x+3y+4z-7)=0
x+y+z-1-2x-3y-4z+7 = 0
⇒ -x+2y+3z-6=0
⇒ x+2y+3z-6=0
Correct option is C
1.
2. There exist where such that .
Which of the above is/are correct?
Statement 1.
Statement 2.
So from the above solution Statements 1 is incorrect and 2nd is also incorrect.
From the given equation
=
= =
Correct (-)
Wrong (-)
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