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NDA - Electrostat Test 1313
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NDA - Electrostat Test 1313
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  • Question 1/5
    1 / -0.33
    Which is NOT true regarding electric field lines
    Solutions

    Properties of electric field lines:

    1. Electric field line is away from a positive charge and towards a negative charge.

    2. Electric field lines make 90 degrees with charge.

    3. Tangent at any point gives direction to the electric field line.

    4. Two electric field lines never cross each other as electric fields.
    Hence option A is correct. 

  • Question 2/5
    1 / -0.33
    What is the energy stored in a 210V charged capacitor of 5?
    Solutions

     Given parameters- Capacitor (C) = 5, Charge (V) = 210

    Energy stored (E) =

    Substituting it we have:

    = 0.110J. Hence, option D is correct

  • Question 3/5
    1 / -0.33
    A charged particle is accelerated by a potential of 200V. If its velocity is , then find out the value of e/m for that particle.
    Solutions

    When a charged particle is accelerated it possesses KE that is equal to the force acting in it.

    If the charge in electron = e

    q = e

     

  • Question 4/5
    1 / -0.33
    An electric dipole moment  is lying along a uniform electric field . Then find out the work done in rotating the dipole by 90°.
    Solutions

    Given that the dipole moment  is lying along the uniform electric field .

    Now, the dipole is rotated by 90o. When an electric dipole is placed in an electric field , a torque  acts on it. This torque tries to rotate the dipole through an angle.

    If the dipole is rotated from an angle  θ1, then work done by an external force is given by

     

  • Question 5/5
    1 / -0.33
    Select the correct options regarding gauss’s law;
    Solutions

    The contribution of flux on the closed surface due to the charges present outside the surface is zero because many field line entering the closed surface is equal to the number of field lines coming out of the surface, so the net contribution of the charge present outside the closed surface to the flux is zero.

    Therefore, the net flux through the surface due to the charge present outside the closed surface is zero. The contribution that counts is only due to the charges present within the closed surface.

    Thus, the flux of the electric field through a closed surface due to all the charges (inside and outside the surface) is equal to the flux due to the charges enclosed by the surface. Hence, option D is correct

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