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Aptitude Test 245
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Aptitude Test 245
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  • Question 1/10
    1 / -0.33

    Profit earned by a shopkeeper on selling 14 kg rice is equal to the cost price of 2 kg rice. If profit is decreased by 30% and the cost price of the rice is Rs.70 per kg, then new selling price is decreased by what percent?

    Solutions

    CP of rice = Rs.70

    14 x SP - 14 x CP = 2 x CP

    SP = 8 x 70/7 = Rs.80

    Profit% = (10/70) x 100 = 100/7%

    New profit% = 70% of 100/7 = 10%

    New selling price = 110% of 70 = Rs.77

    Percentage decrease in selling price = ((80 - 77)/80) x 100 = 3.75%

     

  • Question 2/10
    1 / -0.33

    Find the next term in the series.

    2284, 2260, 2225, 2177, 2114, ?

    Solutions

    The series is as follows:

    2284 - 4 x 6 = 2260

    2260 - 5 x 7 = 2225

    2225 - 6 x 8 = 2177

    2177 - 7 x 9 = 2114

    2114 - 8 x 10 = 2034

     

  • Question 3/10
    1 / -0.33

    Directions For Questions

    Directions : Study the following table carefully and answer the questions given below.

    Number of Males and Females staying in various Cities including children.

    Number of children expressed as percentages of total male and female in the respective cities. Male children and female children are given as percentages of total children.

    ...view full instructions

    What is the difference between the number of male children in City A and the number of female children in City D?

    Solutions

    Number of male children in city A = 800 x 0.35 x 0.5 = 140

    Number of female children in city D = 580 x 0.32 x 0.25 = 29

    Required difference = 140 - 29 = 111

     

  • Question 4/10
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    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    I. x2 -11x -80 = 0

    II. y2 -31y +198 = 0

    Solutions

    From equation I:

    x2 -11x -80 = (x + 5)(x -16)= 0

    => x = -5, 16

    From equation II:

    y2 -31y +198 = (y -22)(y -9) = 0

    => y = 22, 9

    So, relationship cannot be established between x and y

     

  • Question 5/10
    1 / -0.33

    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    I. x2 -8x -65 = 0

    II. y2 +32y +255 = 0

    Solutions

    From equation I:

    x2 -8x -65 = (x -13)(x + 5)= 0

    => x = 13, -5

    From equation II:

    y2 +32y +255 = (y + 15)(y + 17) = 0

    => y = -15, -17

    So, x > y

     

  • Question 6/10
    1 / -0.33

    Akbar and Birbal entered into a partnership and invested Rs 4,000 each. After 5 months, Birbal invested Rs 1,000 more and Chandan entered the partnership investing Rs 6,000. If the share of Chandan was Rs 8,400, what was the profit at the end of the year?

    Solutions

    Profit will be distributed between Akbar, Birbal and Chandan in the ratio

    (4000*12):(4000*5 + 5000*7):(6000*7)

    = 48:55:42

    Sum of parts of the ratio = 48 + 55 + 42 = 145

    Profit at the end of the year = (145/42)*8400 = Rs 29,000

     

  • Question 7/10
    1 / -0.33

    Lucknow and Varanasi are 270 km apart on a straight line. Train A starts from Lucknow at 5:00 am and travels towards Varanasi at 60 km/h. Train B starts from Varanasi at 7:00 am and travels towards Lucknow at a speed of 40 km/h. At what time will they meet?

    Solutions

    Suppose they meet 'x' hours after 5 am.

    Distance travelled by train A in x hours = 60x km.

    Distance travelled by train B in (x - 2) hours = 40 (x - 2) km.

    Therefore, 60x + 40 (x - 2) = 270

    => 100x - 80 = 270

    => 100x = 350

    => x = 3.5hr = 3hr 30 minutes

    So they meet at 8:30 am.

     

     

  • Question 8/10
    1 / -0.33

    Directions For Questions

    Directions : Study the following table carefully and answer the questions given below.

    Number of Males and Females staying in various Cities including children.

    Number of children expressed as percentages of total male and female in the respective cities. Male children and female children are given as percentages of total children.

    ...view full instructions

    What is the total number of female children staying in the B and F Cities together?

    Solutions

    City B → 750*50/100=375

    Number of all female children 375*20/100=75

    City F → 900*32/100=288

    Number of female children = 288*25/100=72

    Total = 147

    Hence, Option 4 is correct.

     

  • Question 9/10
    1 / -0.33

    Directions For Questions

    In each of the following questions, a question is followed by two statements I and II. Read the statements to find the answer to given question and then answer accordingly that which statement/statements can give the answer alone/together.

    ...view full instructions

    The height of Anni is 2.5 ft more than that of Summi. What is the average height of Anni and Summi?

    Statement I: The average height of Anni, Summi, and Rimmi is 6 fts.

    Statement II: The average height of Anni and Rimmi is 6.5 fts.

    Solutions

    Let the height of Anni = a fts

    The height of Summi = a - 2.5 fts

    The height of Rimmi = r fts

    From the statement I,

    a + a - 2.5 + r = 18 fts

    2a + r = 20.5 ----- (i)

    From the statement II,

    a + r = 6.5*2 = 13 ---- (ii)

    from any of the statements alone, we could not determine the value of two unknown

    From I and II together,

    2a + r = 20.5

    a + r = 13

    By solving both the equation, a = 7.5 and r = 5.5

    Therefore, the required average = (a + a - 2.5)/2 = (15 - 2.5)/2 = 12.5/2 = 6.25

     

     

  • Question 10/10
    1 / -0.33

    In each of the following questions, each question is followed by two statements. Read all the statements carefully and find that which of the following statement(s) is/are sufficient to answer the question.

    Sum of present ages of Dhruv, Rakhi, Hema and Shikha is 60 years. What will be the ratio of ages of Rakhi and Hema after 3 years from now?

    Statement I: Ratio of ages of Dhruv and Rakhi after two years will be 2: 1 respectively.

    Statement II: Ratio of ages of Rakhi and Shikha before 3 years was 2: 9 respectively.

    Solutions

    Let present ages of Dhruv, Rakhi, Hema and Shikha are a, b, c and d years respectively.

    a + b + c + d = 62

    From statement I:

    (a + 2): (b + 2)= 2: 1

    a = 2b + 2

    From statement II:

    (b - 3): (d - 3) = 2: 9

    d = (9b - 21)/2

    From statements I and II:

    (2b + 2) + b + c + ((9b - 21)/2) = 62

    15b + 2c = 141

    Hence, given data in both the statements together are not sufficient.

     

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