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NDA - Gravitation Test 1414
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NDA - Gravitation Test 1414
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  • Question 1/5
    1 / -0.33

    Calculate the escape velocity on the surface of a planet of mass 7.5 X  g, its radius 1.6 X  m.

    G = 6.67 X

    Solutions

    Consider the given information

    Escape velocity,

  • Question 2/5
    1 / -0.33

    The dimension of the gravitational field intensity is the same as that of
    Solutions

    Dimensions of Acceleration due to gravity=

    Dimensions of Gravitational Field Intensity=

    Both are having similar physical quantity, that’s why their dimensions are the same.

  • Question 3/5
    1 / -0.33

    What is the weight of a human body on the surface of the moon?
    Solutions

    Mass of an object is the same on the earth as well as the moon, but the weight is different.

    = =

    Where is a mass of earth= kg

    is the radius of earth= m

    is mass of moon= kg

    is the radius of moon= m

    =

    Therefore,

    6

    Hence,

    Weight of a body on earth= 6 (weight of body on moon)

    Weight of body on moon=  (weight of body on earth). Hence, option C is correct.

  • Question 4/5
    1 / -0.33

    Which of the following is not a necessary condition for a

    satellite to be classified as a geostationary satellite?

    Solutions

    Geostationary or synchronous satellites are those satellites that revolve around the earth with similar angular speed and the same direction as the earth does on it axis.

    Geostationary satellites are used for a number of purposes like weather forecasting, studying outer space, mapping the earth, communication, detecting possible asteroid impacts, etc.

    Communication is not their only use.

    Hence C is the correct option.

  • Question 5/5
    1 / -0.33

    The dimensional formula of gravitational constant G, is
    Solutions

    F = M1 L T-2

    = M0 L2 T0

    = M2 L0 T0

    G = M-1 L3 T-2

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