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The equation of the required plane:
⇒
AB =
= = 3
BC =
Ac =
= =
Clearly, AC2 = AB2 + BC2
Therefore, ∆ABC is a right-angled triangle.
Correct Answer is option D
Normal vector of plane will be
Correct Answer is option C
Given that,
The xy-plane divides the line segment joining the points (–1, 3, 4) and (2, –5, 6),
xy-plane it means z- coordinate equal to zero.
So, using line dividing formula
Negative sign denote it divided externally.
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