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After solving,
is defined for all real value of x and is also defined for all real value of x so, tan–1x + cot–1x = is defined for all real value of x.
secθ + cosecθ=,
sinθ + cosθ= sinθcosθ
on squaring, we have
1 + sin2θ = 15 sin2θcos2θ
1+sin2θ=(15/4)sin22θ
15sin2 2θ– 4 sin2θ–4 = 0
sin2θ=(-2/5 , 2/3)
Since 0 < θ < 0 < 2θ < 2
a = 4, b = -8, c =4
a + b + c = 0
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