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NDA - Mathematics HM Test 972
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NDA - Mathematics HM Test 972
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  • Question 1/5
    1 / -0.33
    If  are in H.P. then:
    Solutions

    Given that  are in H.P.

    It is clearly seen that  are in A.P.

  • Question 2/5
    1 / -0.33
    If  are in H.P. and  ,then  are in
    Solutions

    It is given that , are in H.P.

    We know that reciprocal of H.P. is A.P. then,

    ⇒  are in A.P.

    ⇒  are in A.P.

     If each term is multiplied by non zero constant or if a constant is added to or subtracted from each term of an A.P. then resulting sequence is also in A.P.

    ⇒ are in A.P.

    ⇒ are in A.P.

    ⇒  are in A.P.

    ⇒  are in H.P. [ Reciprocal of H.P. is A.P.]

  • Question 3/5
    1 / -0.33
    If  and  are in H.P. , then  and  are in
    Solutions

    It is given that

     are in H.P.

      are in A.P.

     

     

     

     

     

     

      and  are in G.P.

  • Question 4/5
    1 / -0.33
    If x,y and z are in HP then  are in
    Solutions

    If x ,y and z are in HP

    ⇒  are in AP

    Multiply by (x+y+z)

    ⇒  are in AP

    ⇒  are in AP

    Subtract 1 both side

    ⇒  are in AP

    ⇒  are in HP

  • Question 5/5
    1 / -0.33
    If  are in A.P. and  are in G.P., then  will be in
    Solutions

    Given that,  are in A.P. and  are in G.P.

    Then,

    And

    Divide (2) by (1), we get

    Hence,

     will be in H.P.

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