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Solutions
A has exam on Monday.
● D has exam on Tuesday.
Case 1:
Case 2:
Take Case 1: ● Two persons have exam between D and F. F does not have exam on Thursday.
● No one has exam between D and E and they both have exams on different days of the week. So E either has exam on Tuesday or Wednesday but we know that they both have exam on different day so E has exam on Wednesday at 8 a.m.
● A has exam before E but not on Tuesday. So A must has exam on Monday at 11 a.m.
● The number of persons who have exam between A and E is same as G and H. G has exam before H. So 2 persons have between A and E and G has exam before H so G must have exam on Tuesday at 8 a.m. and H on Wednesday at 11 a.m.
● B has exam at 11 a.m. before C but this cannot be possible so this case gets rejected.
Take Case 2: ● Two persons have exam between D and F.
● No one has exam between D and E and they both have exams on different days of the week. So E either has exam on Monday or Tuesday but we know that they both have exam on different day so E has exam on Monday at 11 a.m.
● A has exam before E so A must has exam on Monday at 8 a.m.
● B has exam at 11 a.m. before C So B must have exam on Tuesday at 11 a.m.
● The number of persons who have exam between A and E is same as G and H. So number of persons between A and E is one then the number between G and H must also 1. G has exam before H. So G must has exam on Thursday at 8 a.m. and H after G.
● C must has exam on Wednesday at 8 a.m.
Here is the final table: