There are three departments and Seven employees. Three departments are Finance, Production, and Marketing. Seven Employees are P, Q, R, S, T, U, and V.

1) V works in the Marketing department and S neither works in the Finance department nor the marketing department.

So, S works in the Production Department and V works in the Marketing Department.

2) P, R, and S work in different departments and P works with T in the same department.

We know the position of S but the R and P department is not known to us. So, there will be two cases. In one of the cases, we will assume R belongs to the Finance department and in another belong to the Marketing department.

3) U does not work with S. P and U do not work in the same department. V does not work with U. 

According to the given conditions U cannot work with V, P, and S. We cannot place U in any department in Case 1. So, Case 1 would be eliminated.

4) Only two persons work in the Finance department. Also, according to the given conditions not more than three people work in the same department. So, Q works in the Production department.

The final arrangement is:

Hence, U and R belong to the Finance department.

There are three departments and Seven employees. Three departments are Finance, Production, and Marketing. Seven Employees are P, Q, R, S, T, U, and V.

1) V works in the Marketing department and S neither works in the Finance department nor the marketing department.

So, S works in the Production Department and V works in the Marketing Department.

2) P, R, and S work in different departments and P works with T in the same department.

We know the position of S but the R and P department is not known to us. So, there will be two cases. In one of the cases, we will assume R belongs to the Finance department and in another belong to the Marketing department.

3) U does not work with S. P and U do not work in the same department. V does not work with U. 

According to the given conditions U cannot work with V, P, and S. We cannot place U in any department in Case 1. So, Case 1 would be eliminated.

4) Only two persons work in the Finance department. Also, according to the given conditions not more than three people work in the same department. So, Q works in the Production department.

The final arrangement is:

Hence, Q belongs to the Production department.

There are three departments and Seven employees. Three departments are Finance, Production, and Marketing. Seven Employees are P, Q, R, S, T, U, and V.

1) V works in the Marketing department and S neither works in the Finance department nor the marketing department.

So, S works in the Production Department and V works in the Marketing Department.

2) P, R, and S work in different departments and P works with T in the same department.

We know the position of S but the R and P department is not known to us. So, there will be two cases. In one of the cases, we will assume R belongs to the Finance department and in another belong to the Marketing department.

3) U does not work with S. P and U do not work in the same department. V does not work with U. 

According to the given conditions U cannot work with V, P, and S. We cannot place U in any department in Case 1. So, Case 1 would be eliminated.

4) Only two persons work in the Finance department. Also, according to the given conditions not more than three people work in the same department. So, Q works in the Production department.

The final arrangement is:

S and Q work in the production department. Hence, S works in the Production department.

Six Persons: Somya, Rohit, Chintu, Amit, John, and Preeti.

Number of chocolates: 2, 3, 5, 6, 8, and 10

1) The Number of chocolate Rohit has is the product of John and Chintu’s chocolate.

Rohit chocolates = John’s chocolate* Chintu’s chocolate

We know, 10=5*2 and 6=3*2

So, Rohit could have either 10 chocolates or 6 chocolates. If Rohit has 10 chocolates then John and Chintu could have 5 and 2 chocolates but not necessarily in the same order. If Rohit has 6 chocolates then John and Chintu could have 3 and 2 chocolates but not necessarily in the same order. It gives rise to four cases.

2) Somya has less chocolate than John.

Number of Chocolates John could have is 2, 3, and 5.

If John has two chocolate then the condition that Somya has less chocolate than John could not be followed. So, Cases 2 and 4 are eliminated.

If John has three chocolates then Somya would have 2 chocolates. But, Chintu already has 2 chocolates. So, Case 3 is eliminated.

If John has five chocolates then Somya would have 3 chocolates in Case 1.

3) Amit’s chocolate is the sum of John and Somya's chocolate. Amit does not have the maximum number of chocolates.

Amit’s chocolate = John’s chocolate + Somya’s chocolate.

John has 5 chocolates and Somya has 3 chocolates. So, Amit has 8 chocolates (8=5+3)

4) Preeti would have 6 chocolates because that is the left for Preeti.

The final arrangement is:

Hence, Rohit has the maximum number of chocolates.

Six Persons: Somya, Rohit, Chintu, Amit, John, and Preeti.

Number of chocolates: 2, 3, 5, 6, 8, and 10

1) The Number of chocolate Rohit has is the product of John and Chintu’s chocolate.

Rohit chocolates = John’s chocolate* Chintu’s chocolate

We know, 10=5*2 and 6=3*2

So, Rohit could have either 10 chocolates or 6 chocolates. If Rohit has 10 chocolates then John and Chintu could have 5 and 2 chocolates but not necessarily in the same order. If Rohit has 6 chocolates then John and Chintu could have 3 and 2 chocolates but not necessarily in the same order. It gives rise to four cases.

2) Somya has less chocolate than John.

Number of Chocolates John could have is 2, 3, and 5.

If John has two chocolate then the condition that Somya has less chocolate than John could not be followed. So, Cases 2 and 4 are eliminated.

If John has three chocolates then Somya would have 2 chocolates. But, Chintu already has 2 chocolates. So, Case 3 is eliminated.

If John has five chocolates then Somya would have 3 chocolates in Case 1.

3) Amit’s chocolate is the sum of John and Somya's chocolate. Amit does not have the maximum number of chocolates.

Amit’s chocolate = John’s chocolate + Somya’s chocolate.

John has 5 chocolates and Somya has 3 chocolates. So, Amit has 8 chocolates (8=5+3)

4) Preeti would have 6 chocolates because that is the left for Preeti.

The final arrangement is:

Hence, Preeti has Six chocolates.

Six Persons: Somya, Rohit, Chintu, Amit, John, and Preeti.

Number of chocolates: 2, 3, 5, 6, 8, and 10

1) The Number of chocolate Rohit has is the product of John and Chintu’s chocolate.

Rohit chocolates = John’s chocolate* Chintu’s chocolate

We know, 10=5*2 and 6=3*2

So, Rohit could have either 10 chocolates or 6 chocolates. If Rohit has 10 chocolates then John and Chintu could have 5 and 2 chocolates but not necessarily in the same order. If Rohit has 6 chocolates then John and Chintu could have 3 and 2 chocolates but not necessarily in the same order. It gives rise to four cases.

2) Somya has less chocolate than John.

Number of Chocolates John could have is 2, 3, and 5.

If John has two chocolate then the condition that Somya has less chocolate than John could not be followed. So, Cases 2 and 4 are eliminated.

If John has three chocolates then Somya would have 2 chocolates. But, Chintu already has 2 chocolates. So, Case 3 is eliminated.

If John has five chocolates then Somya would have 3 chocolates in Case 1.

3) Amit’s chocolate is the sum of John and Somya's chocolate. Amit does not have the maximum number of chocolates.

Amit’s chocolate = John’s chocolate + Somya’s chocolate.

John has 5 chocolates and Somya has 3 chocolates. So, Amit has 8 chocolates (8=5+3)

4) Preeti would have 6 chocolates because that is the left for Preeti.

The final arrangement is:

Chintu has 2 chocolates and Amit has 8 chocolates. So, the difference between Chintu and Amit chocolate is Six.

1) A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not neighbour of T.

5) R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

Hence, T is sitting opposite to E.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not a neighbour of T.

5) R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

Hence, Both 1 and 2 (RC and BQ) are sitting diagonally opposite to each other.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not a neighbour of T.

5) R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

Here, opposite of R is B

And 3rd to the right of B is D

Hence, D is third to the right of the one who is opposite to R.

1)  A is sitting opposite to the one who is second to the right of Q. 

2) Q is sitting at the end of the row (either left or right)

So, Q will sit at the right end of the row:

3) A and D are immediate neighbours of each other and D is second to the right of E:

So, D will sit to the immediate right of A.

4) S is third to the left of R and is not neighbour of T.

5) R is opposite to B.

So, B will sit immediate left of E and C will sit to the immediate right of D:

Here, S is not the neighbour of T, so T will sit immediate left of R and P will sit immediate right of S.

So, the final figure according to the question is:

Here, R, C, Q, B are sitting at the end of the rows except P.

Hence, P does not belong to that group.