Boxes – 7; Q, R, S, T, U, V and W;

Number of chocolates – 7; 38, 49, 60, 67, 76, 83 and 92;  

1. Three boxes are placed between Q and the box which has perfect square number of chocolates.

2. Q is placed immediately above R.

3. T has twice the number of chocolates with R.

From this we get the possible arrangement as follows. Hence, we can say that T has 76 chocolates in both the cases.

4. Five boxes are placed between R and S.

From this we can say that case 1 is eliminated, as we cannot place S.

5. The number of boxes placed above W is the same as the number of boxes placed below V.

6. The difference between the number of chocolates between R and S is twice the difference between the number of chocolates between S and U.

From this we can say that as R has 38 chocolates and U has 60 chocolates, hence, we can say that S has 60 chocolates. W and V are placed third from the ends, in any order. T is placed in the middle of the stack.

From this we get the arrangement as follows.

7. W is placed immediately above the box which has the highest number of chocolates but has more chocolates than T.

From this we get the final arrangement as follows.

No boxes are placed between the boxes which has the least and the highest number of chocolates.

Hence, none is the correct answer.

Boxes – 7; Q, R, S, T, U, V and W;

Number of chocolates – 7; 38, 49, 60, 67, 76, 83 and 92;  

1. Three boxes are placed between Q and the box which has perfect square number of chocolates.

2. Q is placed immediately above R.

3. T has twice the number of chocolates with R.

From this we get the possible arrangement as follows. Hence, we can say that T has 76 chocolates in both the cases.

4. Five boxes are placed between R and S.

From this we can say that case 1 is eliminated, as we cannot place S.

5. The number of boxes placed above W is the same as the number of boxes placed below V.

6. The difference between the number of chocolates between R and S is twice the difference between the number of chocolates between S and U.

From this we can say that as R has 38 chocolates and U has 60 chocolates, hence, we can say that S has 60 chocolates. W and V are placed third from the ends, in any order. T is placed in the middle of the stack.

From this we get the arrangement as follows.

7. W is placed immediately above the box which has the highest number of chocolates but has more chocolates than T.

From this we get the final arrangement as follows.

Hence, the sum of the number of chocolates with T and S is  76 + 60 = 136.

Boxes – 7; Q, R, S, T, U, V and W;

Number of chocolates – 7; 38, 49, 60, 67, 76, 83 and 92;  

1. Three boxes are placed between Q and the box which has perfect square number of chocolates.

2. Q is placed immediately above R.

3. T has twice the number of chocolates with R.

From this we get the possible arrangement as follows. Hence, we can say that T has 76 chocolates in both the cases.

4. Five boxes are placed between R and S.

From this we can say that case 1 is eliminated, as we cannot place S.

5. The number of boxes placed above W is the same as the number of boxes placed below V.

6. The difference between the number of chocolates between R and S is twice the difference between the number of chocolates between S and U.

From this we can say that as R has 38 chocolates and U has 60 chocolates, hence, we can say that S has 60 chocolates. W and V are placed third from the ends, in any order. T is placed in the middle of the stack.

From this we get the arrangement as follows.

7. W is placed immediately above the box which has the highest number of chocolates but has more chocolates than T.

From this we get the final arrangement as follows.

Except W, T, in other options, first box is placed above the second box.

Hence, W, T is the odd man out.

Boxes – 7; Q, R, S, T, U, V and W;

Number of chocolates – 7; 38, 49, 60, 67, 76, 83 and 92;  

1. Three boxes are placed between Q and the box which has perfect square number of chocolates.

2. Q is placed immediately above R.

3. T has twice the number of chocolates with R.

From this we get the possible arrangement as follows. Hence, we can say that T has 76 chocolates in both the cases.

4. Five boxes are placed between R and S.

From this we can say that case 1 is eliminated, as we cannot place S.

5. The number of boxes placed above W is the same as the number of boxes placed below V.

6. The difference between the number of chocolates between R and S is twice the difference between the number of chocolates between S and U.

From this we can say that as R has 38 chocolates and U has 60 chocolates, hence, we can say that S has 60 chocolates. W and V are placed third from the ends, in any order. T is placed in the middle of the stack.

From this we get the arrangement as follows.

7. W is placed immediately above the box which has the highest number of chocolates but has more chocolates than T.

From this we get the final arrangement as follows.

Box W is placed third from bottom,

Hence, box T is placed immediately above box W.

The pattern followed here is:

1) NS → N + 5 = S

2) IM → I + 4 = M

3) UY → U + 4 = Y

4) KO → K + 4 = O

5) FJ → F + 4 = J

Thus, NS does not fulfil the above condition. So, it is the odd one out from the given options.

Given:

Seven persons: Purvi, Jay, Vijay, Jagruti, Hina, Kamal, and Rajesh.

Seven companies: Adobe, Microsoft, Google, Mivi, Oyo, Apple, and Byjus.

Seven professions: Site manager, Head of Sales, Marketing head, App developer, HR manager, Testing engineer, and Software engineer.

i) Purvi is a Software engineer and works in Google.

ii) One of them works in Mivi as a Testing engineer.

iii) Kamal works in Byjus and Jay works in Apple.

iv) Neither Jagruti nor Vijay works in Oyo.

v) Hina is the Head of Sales in one of the companies.

vi) The one who is a Site manager works in Microsoft.

vii) Jagruti is a Marketing head in a company.

viii) Rajesh is not a Site manager.

This simplifies that Vijay works in Microsoft and Rajesh works in Mivi.

So, the final arrangement is,

Hence, 'Jagruti' works in Adobe.

Given:

Seven persons: Purvi, Jay, Vijay, Jagruti, Hina, Kamal, and Rajesh.

Seven companies: Adobe, Microsoft, Google, Mivi, Oyo, Apple, and Byjus.

Seven professions: Site manager, Head of Sales, Marketing head, App developer, HR manager, Testing engineer, and Software engineer.

i) Purvi is a Software engineer and works in Google.

ii) One of them works in Mivi as a Testing engineer.

iii) Kamal works in Byjus and Jay works in Apple.

iv) Neither Jagruti nor Vijay works in Oyo.

v) Hina is the Head of Sales in one of the companies.

vi) The one who is a Site manager works in Microsoft.

vii) Jagruti is a Marketing head in a company.

viii) Rajesh is not a Site manager.

This simplifies that Vijay works in Microsoft and Rajesh works in Mivi.

So, the final arrangement is,

Vijay works in Microsoft as a Site manager.

Hence, 'Vijay - HR manager' is a wrong pair.

Given:

Seven persons: Purvi, Jay, Vijay, Jagruti, Hina, Kamal, and Rajesh.

Seven companies: Adobe, Microsoft, Google, Mivi, Oyo, Apple, and Byjus.

Seven professions: Site manager, Head of Sales, Marketing head, App developer, HR manager, Testing engineer, and Software engineer.

i) Purvi is a Software engineer and works in Google.

ii) One of them works in Mivi as a Testing engineer.

iii) Kamal works in Byjus and Jay works in Apple.

iv) Neither Jagruti nor Vijay works in Oyo.

v) Hina is the Head of Sales in one of the companies.

vi) The one who is a Site manager works in Microsoft.

vii) Jagruti is a Marketing head in a company.

Hence, profession of Jay is either App developer or HR manager.

Given,

Seven persons: Purvi, Jay, Vijay, Jagruti, Hina, Kamal, and Rajesh.

Seven companies: Adobe, Microsoft, Google, Mivi, Oyo, Apple, and Byjus.

Seven professions: Site manager, Head of Sales, Marketing head, App developer, HR manager, Testing engineer, and Software engineer.

i) Purvi is a Software engineer and works in Google.

ii) One of them works in Mivi as a Testing engineer.

iii) Kamal works in Byjus and Jay works in Apple.

iv) Neither Jagruti nor Vijay works in Oyo.

v) Hina is the Head of Sales in one of the companies.

vi) The one who is a Site manager works in Microsoft.

vii) Jagruti is a Marketing head in a company.

viii) Rajesh is not a Site manager.

This simplifies that Vijay works in Microsoft and Rajesh works in Mivi.

So, the final arrangement is,

Hence, if App developer works in Byjus then HR manager will be working in 'Apple'.

Given,

Seven persons: Purvi, Jay, Vijay, Jagruti, Hina, Kamal, and Rajesh.

Seven companies: Adobe, Microsoft, Google, Mivi, Oyo, Apple, and Byjus.

Seven professions: Site manager, Head of Sales, Marketing head, App developer, HR manager, Testing engineer, and Software engineer.

i) Purvi is a Software engineer and works in Google.

ii) One of them works in Mivi as a Testing engineer.

iii) Kamal works in Byjus and Jay works in Apple.

iv) Neither Jagruti nor Vijay works in Oyo.

v) Hina is the Head of Sales in one of the companies.

vi) The one who is a Site manager works in Microsoft.

vii) Jagruti is a Marketing head in a company.

viii) Rajesh is not a Site manager.

This simplifies that Vijay works in Microsoft and Rajesh works in Mivi.

So, the final arrangement is,

Hence, Rajesh works in 'Mivi' as a 'Testing engineer'.