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Solutions
Given:
Time taken to complete the whole work by A = 7 days
Time taken to complete the whole work by B = 14 days
Number of days A and B worked together = 4 days
Concept used:
If A and B can do a piece of work in 'x' days and 'y' days, respectively.
They start working together and after 't' days B leaves the work,
then the time taken to finish the whole work will be [(x/y) × (y - t)] days.
Calculation:
Here, x = 7 days, y = 14 days, t = 4 days
As we know that
Required time = [(x/y) × (y - t)] days
⇒ [(7/14) × (14 - 4)]
⇒ (1/2) × 10
⇒ 5 days
∴ Total work would be finished in 5 days.
Alternate Method
Calculation:
One day work of (A + B) = (1/7) + (1/14)
⇒ (3/14) units
Work done by (A + B) in 4 days = 4 × (3/14)
⇒ (6/7) units
Remaining Work = 1 - (6/7)
⇒ (1/7) units
Since B left after 4 days.
Remaining work done by A = (1/7) units
Time taken by A to do remaining work = [(1/7)/(1/7)] days
⇒ 1 day
So, Total days = (4 + 1) days
⇒ 5 days
∴ Total work would be finished in 5 days.