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Arithmetical Reasoning Test 478
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Arithmetical Reasoning Test 478
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  • Question 1/10
    1 / -0.25
    Vishal borrows some X amount of money for one year from Ravi at the rate of 8% per annum. He pays ₹2,240 as annual interest for the borrowed amount. Find the value of X.
    Solutions

    Since the amount is borrowed for 1-year, simple interest and compound interest will be the same. Thus, we apply the formula of simple interest.

    x = 28000

    Hence, option D is the correct answer.

  • Question 2/10
    1 / -0.25
    If one is subtracted from each prime number and one is added to each even composite number in the number 341261750, what will be the resultant number?
    Solutions

    Prime number – 1

    Even composite number + 1

    1 and 0 are neither prime nor composite.

    Hence, option C is the correct answer.

  • Question 3/10
    1 / -0.25
    The present ages of A and B are 32 years and 24 years respectively. What will be the ratio of ages of A and B after 8 years?
    Solutions
    A’s age is 32

    B’s age is 24

    After 8 years ages of A and B will be: 40 and 32

    Ratio of their ages will be

    A:B = 40:32 = 5:4

    Hence, option A is the correct answer.
  • Question 4/10
    1 / -0.25
    What is the difference between the compound interest on ₹40,000 at 20% per annum compounded half-yearly and compounded quarterly for a period of one year?
    Solutions

    Solving, we get –

    Difference between the CIs = ₹ 220.25

    Hence, option D is the correct answer.

  • Question 5/10
    1 / -0.25
    When 12 is added to a number, it is equal to 2 times the sum of 4 and the number. Find the number.
    Solutions

    Let Number is – x

    x + 12 = 2 (4 + x)

    x + 12 = 8 + 2x

    2x – x = 12 – 8

    X = 4

    Hence, option D is the correct answer.

  • Question 6/10
    1 / -0.25
    A number is subtracted from 4 times of it and then, the number obtained is added to its (the resultant’s) next number. If this gives the answer as 91, what was the original number?
    Solutions

    Let the number is x

    A.T.Q

    4x – x = 3x

    3x + 3x + 1 = 91

    6x + 1 = 91

    6x = 90

    X = 15

    Hence, option D is the correct answer.

  • Question 7/10
    1 / -0.25
    Neha wants to sell an item. How many times of the cost price should be the selling price, if she wants to earn 200% profit?
    Solutions

    Let the C.P. be Rs x.

    For 200% profit

    S.P. =  = 3x

    Thus, S.P. should be 3 times that if C.P.

    Hence, option C is the correct answer.

  • Question 8/10
    1 / -0.25
    A bicycle is sold at Rs.53,760 with a profit of 12%. At what price did the seller buy the bicycle?
    Solutions

    Let the C.P. be Rs x.

    Thus,

    x = Rs. 48000.

    Thus, the C.P. of the bicycle is Rs. 48000.

    Hence, option C is the correct answer.

  • Question 9/10
    1 / -0.25
    In a class of 98 students, all play at least one of the three games – snooker, chess and tennis. 42 students play snooker, 49 play tennis, and 43 play chess. The total number of students who play any and only two games is 29. 5 students play all the three games. The number of students who play only snooker and only chess is equal. 11 students play only snooker and tennis. 6 students play only snooker and chess. How many students play only tennis?
    Solutions

    Total number of students = 98

    Students play snooker = 42

    Students play all the three games = 5

    Students play only snooker and tennis = 11

    Students play only snooker and chess = 6

    So, player only play snooker = 42 – (6 + 5 + 11) = 20

    So, player only play chess and tennis = 43 – (20 + 6 + 5) = 12

    So, only play chess = 20

    So, only play tennis = 49 – (12 + 5 + 11) = 21


    Hence, option A is the correct answer.

  • Question 10/10
    1 / -0.25
    Mohit and Sudesh bought pens and notebooks from the same shop. Mohit bought 3 pens and 6 notebooks by paying an amount of Rs 180. Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs 116. How much did Mohit spend on buying notebooks?
    Solutions

    3P + 6N = 180 or,

    1P + 2N = 60…….. (1)

    5P + 2N = 116……… (2)

    Subtracting (1) from 2 we get,

    4P=56
    P= Rs.14

    Putting the value in eq 1,

    6N = 180- 42

    6N= 138

    Hence, option B is the right answer.

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