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Heat Transfer Test - 1
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    Calculate the energy radiated per second from the filament of an incandescent lamp at 2000 K if the surface area is 5.0 x 10–5 m2 and its relative emittance is 0.85. (σ = 5.7 x 10–8 W m–2 K–4)

     

    Solutions

    Explanation:We know E = AeσT4

    Here, A = 5.0 x 10–5 m2

    σ = 5.7 x 10–8 W m–2 K–4

    e = 0.85, T = 2000k

    ∴  E = 5.0 x 10–5 m2 x 0.85 x 5.7 x 10–8 W–2 K–4 x (2000)4 K4

    = 38.76 W = 38.76 J s–1

     

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