Please wait...

Chemistry Test 100
Menu grid icon
Result Result point icon
Chemistry Test 100
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/8
    4 / -1

    Hybridisation of which complex in correctly matched :-

    Solutions

    (A) AuCl4– – dsp2

    (B) [Co(OX)3]3– – d2sp3

    (C) RhCl(PPh3)3 – dsp2

    (D) [Fe(NH3)6]2+ – sp3d2

     

  • Question 2/8
    4 / -1

    Coinage metals show properties of :-

    Solutions

    Cu,Ag, Au

     

  • Question 3/8
    4 / -1

    Oxidation state of K in K2O, K2O, KO2 :-

    Solutions

    Oxidation state of o in superoxide is (–1/2) & in peroxide is (–1).

     

  • Question 4/8
    4 / -1

    Metal with low melting point contains impurities of high melting point can be purified by :

    Solutions

    Liquation is used for metals having impurities with high melting point..

     

  • Question 5/8
    4 / -1

    n = 5, ms = –1/2, How many orbitals are possible :-

    Solutions

    According to (n + ℓ) rule

    n = 5

    5s → 1 (orbital)

    5p → 3

    5d → 5

    5f → 7

    5g → 9

    ⇒ 5H not possible

     

  • Question 6/8
    4 / -1

    The radius of La+3 is 1.06 Å, which of the following given values will be closest to the radius of Lu+3 (atomic no. of La = 57) (atomic no. of Lu is 71).

  • Question 7/8
    4 / -1

    Which of the following pair will release maximum energy on gaining one electron :-

    Solutions

    Electron affinity increases across period and   decreases down the group.

     

  • Question 8/8
    4 / -1

    Nitriles can be converted into Amine by reaction with :-

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now