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Chemistry Test 105
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Chemistry Test 105
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  • Question 1/10
    4 / -1

    The compound Na2IrCl6 reacts with triphenylphosphine in diethyleneglycol in an atmosphere of CO to give [IrCl(CO)(PPh3)2], known as 'Vaska's compound'. (Atomic number of Ir = 77) Which of the following statements is correct?

    Solutions

    (A)    [1rCl(CO)(PPh3)2] carbonylchloridobis (triphenylphosphine) iridium(I).

    (B)    Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d8 configuration. It is trans isomer, so its geometry should be square planar.

    (C)    All electrons are paired, hence diamagnetic 

    (D)    Can exhibit GI only.

     

  • Question 2/10
    4 / -1

    The cell shown below generates a potential of 0.643 V at 300 K. Find (log Ksp) for AgBr: 

    Ag|AgBr(s)|NaBr(0.1 M)||AgNO3(0.1 M)|Ag 

    Solutions

     

     

  • Question 3/10
    4 / -1

    Incorrectly matched reaction among the following is :

    Solutions

    Ferdal Craft reaction not shown by Highly Activated Rings.

     

  • Question 4/10
    4 / -1

    Choose the incorrect statement from the following:

    Solutions

    The slag formed is CaSIO3 which is lighter and has less melting point.

     

  • Question 5/10
    4 / -1

    We have taken a saturated solution of AgBr. Ksp of AgBr is 12 × 10–14.  If 10–7 mole of AgNO3 are added to 1 litre of this solution find conductivity (specific conductance) of this solution in terms of 10–7 S m–1 units.

    Solutions

                     S + 10–7                S

    (S + 10–7)S = 12 × 10–14

    ∴    S = 3 × 10–7 M

    [Ag+] = 4 × 10–7 M

    [Br–] = 3 × 10–7 M

    [NO3–] = 10–7 M

    κtotel = [6 × 4 × 10–7] + [8 × 3 × 10–7] + [7 × 1 × 10–7]

    = 55 × 10–7 S m–1

     

  • Question 6/10
    4 / -1

    Incorrect order of Rate of Reduction among the following is :

    Solutions

    DiBAL-H is electron deficient reducing agent as Burane and readily reduces electron rich sp.

     

  • Question 7/10
    4 / -1

    Which of the following cation produces ppt. with only one of the given condition

    (I) In aqueous solution produce ppt with dil. HCl

    (II) In acidic aqueous solution produce ppt with H2S

    Solutions

    A, B and C can be precipitated by HCl as well as H2S as their insoluble chlorides and sulphides.

    (D) Sn+2 can be precipitated by H2S but not by HCl

    Sn+2 + 2HCl → SnCl2(soluble)

     

  • Question 8/10
    4 / -1

    Select the incorrect statement. 

    Solutions

    Kiliani Fischer method is for upgradation of C-chain.

     

  • Question 9/10
    4 / -1

    Select the INCORRECT statement:

    Solutions

    At Boyle's Temperature; gas behaves ideally for a range of pressure.

     

  • Question 10/10
    4 / -1

    Directions For Questions

    ...view full instructions

    How many statements are correct?

    (i) P1 is H2N – CO(–CH2)3 – CH2CO2H 

    (ii) P2 is H2N – (CH2)3 – CH2CO2H

    (iii) P3 is H2N – (CH2)3 – CH(Br) – CO2H

    (iv) P4 is

    Solutions

    All are correct

     

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