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Solutions
Total volume = 500 + 1500 = 2000 ml = 2L
Moles of [Na+] ions = 0.2 × 0.5 = 0.1
Concentration of [Na+] ions = 0.1/2 = 0.0M
Moles of [Mg2+] ions = 0.4 × 1.5 = 0.6
Concentration of [Mg2+] ions
= 0.6/2 = 0.3M = 7.2gm/L
Moles of [Cl–] ions = 0.2 × 0.5 + 2 × 0.4 × 1.5 = 1.3
Concentration of [Cl–] ions = 1.3/2 = 0.65 M