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Alternating Current Test - 22
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Alternating Current Test - 22
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  • Question 1/10
    4 / -1
    A virtual current of 4 A and 50 Hz flows in an ac circuit containing a coil. The power consumed in the coil is 240 W. If the virtual voltage across the coil is 100 V its inductance will be
    Solutions

  • Question 2/10
    4 / -1
    A circuit draws 330 W from a 110 V, 60 Hz ac line. The power factor is 0.6 and the current lags the voltage. The capacitance of a series capacitor that will result in a power factor of unity is equal to
    Solutions

  • Question 3/10
    4 / -1
    In the adjoining figure the impedance of the circuit will be

    Solutions

  • Question 4/10
    4 / -1
    The figure shows variation of R, XL and XC with frequency f in a series L,C,R circuit. Then for what frequency point, the circuit is inductive

    Solutions

  • Question 5/10
    4 / -1
    When an ac source of e.m.f. e = E0 sin(100t) is connected across a circuit, the phase difference between the e.m.f. e and the current iin the circuit is observed to be π/4, as shown in the diagram. If the circuit consists possibly only of RC or LC in series, find the relationship between the two elements

    Solutions

  • Question 6/10
    4 / -1
    A bulb and a capacitor are in series with an ac source. On increasing frequency how will glow of the bulb change
    Solutions

  • Question 7/10
    4 / -1
    What is the r.m.s. value of an alternating current which when passed through a resistor produces heat which is thrice of that produced by a direct current of 2 amperes in the same resistor
    Solutions

  • Question 8/10
    4 / -1

    Solutions

  • Question 9/10
    4 / -1
    In an LCR circuit R = 100 ohm. When capacitance C is removed, the current lags behind the voltage by π/3. When inductance L is removed, the current leads the voltage by π/3. The impedance of the circuit is
    Solutions

  • Question 10/10
    4 / -1
    A group of electric lamps having a total power rating of 1000 watt is supplied by an ac voltage E = 200 sin(310t + 60° ). Then the r.m.s. value of the circuit current is
    Solutions

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