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Alternating Current Test - 29
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Alternating Current Test - 29
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  • Question 1/10
    4 / -1
    The mutual inductance between two coils depends on
  • Question 2/10
    4 / -1
    In Fig. maximum deflection in galvanometer G occurs when

  • Question 3/10
    4 / -1
    A coil has an area of 0.05 m2 and has 800 turns. After placing the coil in a magnetic field of strength 4×10-5 Wb/m2, perpendicular to the field, the coil is rotated through 90o in 0.1 s. the average e.m.f. induced is
    Solutions

  • Question 4/10
    4 / -1
    In Fig. final value of current in 30 Ω resistor, when plug of key K is inserted is

    Solutions

  • Question 5/10
    4 / -1
    A dynamo dissipates 20watt, when it supplies a current of 4 amp. Through it. If the terminal potential difference is 220 volt, the e.m.f produced is
    Solutions

  • Question 6/10
    4 / -1
    A long solenoid of length l, cross section A, having N1 turns has wound about its centre a small coil of N2 turns as shown. Then the mutual inductance of the two circuit is

    Solutions

  • Question 7/10
    4 / -1
    There are several methods of achieving electric energy such as by electrostatic generator, electro-magnetic generator, battery, thermocouple, photoelectric cells. From the point of view of electric energy, the choices can be arranged as
  • Question 8/10
    4 / -1
    The current from A to B is increasing in magnitude. What is the direction of induced current, if any, in the loop shown in Fig.

  • Question 9/10
    4 / -1
    A copper ring having a cut such as not to form a complete loop is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet is

  • Question 10/10
    4 / -1
    A square loop of wire of side 5 cm is lying on a horizontal table. An electromagnet above and to one side of the loop is turned on, causing a uniform magnetic field downwards at an angle of 60o to the vertical as shown in fig. The magnetic induction is 0.50 T. The average induced e.m.f in the loop, if the field increases from zero to its final value in 0.2s is

    Solutions

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