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Alternating Current Test - 55
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Alternating Current Test - 55
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  • Question 1/10
    4 / -1
    The reading of ammeter in the circuit shown will be

    Solutions

  • Question 2/10
    4 / -1
    An ac source of angular frequency ω is fed across aresistor r and a capacitor C in series. The currentregistered is I. If the frequency of source is changed to ω /3 (maintaining the same voltage), the current in thecircuit is found to be halved. Calculate the ratio ofreactance to resistance at the original frequency ω
    Solutions

  • Question 3/10
    4 / -1
    Is it possible

    Solutions

  • Question 4/10
    4 / -1
    A virtual current of 4 A and 50 Hz flows in an ac circuit containing a coil. The power consumed in the coil is 240 W. If the virtual voltage across the coil is 100 V its inductance will be
    Solutions

  • Question 5/10
    4 / -1
    In the adjoining ac circuit the voltmeter whose readingwill be zero at resonance is

  • Question 6/10
    4 / -1
    In the inductive circuit given in the figure, the current rises after the switch is closed. At instant when thecurrent is 15 mA, then potential difference across theinductor will be

    Solutions

  • Question 7/10
    4 / -1
    Which one of the following curves represents the variation of impedance (Z) with frequency f in series LCR circuit
    Solutions

  • Question 8/10
    4 / -1
    The variation of the instantaneous current (I) and the instantaneous e.m.f. (E) in a circuit is as shown in fig. Which of the following statement is correct?

    Solutions

  • Question 9/10
    4 / -1
    The figure shows variation of R, XL and XC with frequency f in a series L, C, R circuit. Then for what frequency point, the circuit is inductive

    Solutions

  • Question 10/10
    4 / -1
    An alternating e.m.f. is applied across a parallel combination of a resistance R, capacitance C and an inductance L. If IR, IL, ICare the currents through R, L and C respectively, then the diagram which correctly represents the phase relationship among IR, IL, ICand source e.m.f. E, is given by
    Solutions

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