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Home
Wave Optics Test - 32
Wave Optics Test - 32
Result
Wave Optics Test - 32
/
Score
-
Rank
Time Taken:
-
Question
1/10
4 / -1
In Young\'s double slit experiment, the fringe width is 1 × 10
–4
m. If the distance between the slit and screen is doubled and the distance between the two slit is reduced to half and wavelength is change from 6.4 × 10
–7
m to 4.0 × 10
–7
m, the value of new fringe width will be
Correct
Wrong
Skipped
A
0.15 × 10
–4
m
Correct
Wrong
Skipped
B
2.0 × 10
–4
m
Correct
Wrong
Skipped
C
1.25 × 10
–4
m
Correct
Wrong
Skipped
D
2.5 × 10
–4
m
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Solutions
Question
2/10
4 / -1
In Young\'s experiment, one slite is covered with a blue filter and the other (slit) with a yellow filter. Then the interference pattern
Correct
Wrong
Skipped
A
Will be blue
Correct
Wrong
Skipped
B
Will be yellow
Correct
Wrong
Skipped
C
Will be green
Correct
Wrong
Skipped
D
Will not be formed
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Solutions
Question
3/10
4 / -1
Two sources give interference pattern which is observed on a screen, D distance apart from the sources. Then fringe width is 2w. If the distance D is now doubled, the fringe width will
Correct
Wrong
Skipped
A
Become w/2
Correct
Wrong
Skipped
B
Remain the same
Correct
Wrong
Skipped
C
Become w
Correct
Wrong
Skipped
D
Become 4 w
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Solutions
Question
4/10
4 / -1
In double slit experiment, the angular width of the fringes is 0.20° for the sodium light (λ = 5890Å). In order to increase the angular width of the fringes by 10%, the necessary change in the wavelength is
Correct
Wrong
Skipped
A
Increase of 589 Å
Correct
Wrong
Skipped
B
Decrease of 589 Å
Correct
Wrong
Skipped
C
Increase of 6479 Å
Correct
Wrong
Skipped
D
Zero
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Solutions
Question
5/10
4 / -1
In a biprism experiment, by using light of wavelength 5000 Å, 5 mm wide fringes are obtained on a screen 1.0 m away from the coherent sources. The separation between the two coherent sources is
Correct
Wrong
Skipped
A
1.0 mm
Correct
Wrong
Skipped
B
0.1 mm
Correct
Wrong
Skipped
C
0.1 mm
Correct
Wrong
Skipped
D
0.01 mm
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Solutions
Question
6/10
4 / -1
The slits in a Young\'s double slit experiment have equal widths and the source is placed symmetrically relative to the slits. The intensity at the central fringes is I
0
. If one of the slits is closed, the intensity at this point will be
Correct
Wrong
Skipped
A
I
0
Correct
Wrong
Skipped
B
I
0
/ 4
Correct
Wrong
Skipped
C
I
0
/ 2
Correct
Wrong
Skipped
D
4 I
0
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Solutions
Question
7/10
4 / -1
In a Young\'s double slit experiment, the fringe width will remain same, if (D = distance between screen and plane of slits. d = separation between two slits and λ = wavelength of light used)
Correct
Wrong
Skipped
A
Both λ and D are doubled
Correct
Wrong
Skipped
B
Both d and D are doubled
Correct
Wrong
Skipped
C
D is doubled but d is halved
Correct
Wrong
Skipped
D
λ is doubled but d is halved
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Solutions
Question
8/10
4 / -1
In a Young\'s double slit experiment the intensity at a point where the path difference λ/6 (λ being the wavelength of the light used) is I. If I
0
denotes the maximum intensity, I/ I
0
is equal to
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
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Solutions
Question
9/10
4 / -1
In Young\'s double slit experiment, angular width of fringes is 0.20° for sodium light of wavelength 5890 Å. If complete system is dipped in water, then angular width of fringes becomes
Correct
Wrong
Skipped
A
0.11°
Correct
Wrong
Skipped
B
0.15°
Correct
Wrong
Skipped
C
0.22°
Correct
Wrong
Skipped
D
0.30°
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Solutions
Question
10/10
4 / -1
In Young\'s double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be
Correct
Wrong
Skipped
A
5000 Å
Correct
Wrong
Skipped
B
6000 Å
Correct
Wrong
Skipped
C
7000 Å
Correct
Wrong
Skipped
D
8000 Å
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Solutions
Re-attempt
-
Correct (
-
)
Wrong (
-
)
Skipped (
-
)
1
2
3
4
5
6
7
8
9
10
Re-attempt
-
Correct (
-
)
Wrong (
-
)
Skipped (
-
)
1
2
3
4
5
6
7
8
9
10
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