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Wave Optics Test - 35
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Wave Optics Test - 35
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  • Question 1/10
    4 / -1
    In Young\'s double slit experiment the wavelength of light was changed from 7000 Å to 3500 Å. While doubling the separation between the slits which of the following is not true for this experiment
    Solutions

  • Question 2/10
    4 / -1
    In a Young\'s double slit experiment, the slit separation is 1 mm and the screen is lm from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is
    Solutions

  • Question 3/10
    4 / -1
    In Young\'s double-slit experiment the fringe width is β. If entire arrangement is placed in a liquid of refractive index n, the fringe width becomes
    Solutions

  • Question 4/10
    4 / -1
    In which of the following is the interference due to the division of wave front?
  • Question 5/10
    4 / -1
    If the separation between slits in Young\'s double slit experiment is reduced to 1/3 rd, the fringe width becomes n times. The value of n is
    Solutions

  • Question 6/10
    4 / -1
    In an experiment of Newton\'s rings, the diameter of the 20th dark ring was found to be 5.82 mm and that of the 10th ring 3.36 mm. If the radius of the plano-convex lens is 1 m, the wavelength of light used is
    Solutions

  • Question 7/10
    4 / -1
    The two slits at a distance of 1 mm are illuminated by the light of wavelength 6.5 × 10–7 m. The interference fringes are observed on a screed placed at a distance of lm. The distance between third dark fringe and fifth bright fringe will be
    Solutions

  • Question 8/10
    4 / -1
    Two coherent sources of intensity ratio 1 : 4 produce an interference pattern. The fringe visibility will be
    Solutions

  • Question 9/10
    4 / -1
    In Young\'s double slit experiment the amplitudes of two sources are 3α and a respectively. The ratio of intensities of bright and dark fringes will be
    Solutions

  • Question 10/10
    4 / -1
    In Young\'s double slit experiment, distance between two sources 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is 5460 Å. Then angular position of the first dark fringe is
    Solutions

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