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Home
Wave Optics Test - 63
Wave Optics Test - 63
Result
Wave Optics Test - 63
/
Score
-
Rank
Time Taken:
-
Question
1/10
4 / -1
Two light rays having the same wavelength λ in vacuum are in phase initially. Then, the first ray travels a path L
1
through a medium of refractive index n
1
while the second ray travels a path of length L
2
through a medium of refractive index n
2
. The two waves are then combined to produce interference. The phase difference between the two waves is
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
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Solutions
Question
2/10
4 / -1
Using the expression 2d sin θ = λ, one calculates the value of d by measuring the corresponding angles θ in the range 0 to 90°. The wavelength λ is exactly known and the error in θ is constant for all values of θ. As, increases from 0°
Correct
Wrong
Skipped
A
the absolute error in d remains constant
Correct
Wrong
Skipped
B
the absolute error in d increases
Correct
Wrong
Skipped
C
the fractional error in d remains constant
Correct
Wrong
Skipped
D
the fractional error in d decreases
Question
3/10
4 / -1
The condition for diffraction of mth order minima is
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Question
4/10
4 / -1
Correct
Wrong
Skipped
A
2000 V
Correct
Wrong
Skipped
B
50 V
Correct
Wrong
Skipped
C
500 V
Correct
Wrong
Skipped
D
1000 V
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Solutions
Question
5/10
4 / -1
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Question
6/10
4 / -1
Wave property of electrons implies that they will show diffraction effects. Davisson and Germer demonstrated this by diffracting electrons from crystals. The law governing the diffraction from a crystal is obtained by requiring that electron waves reflected from the planes of atoms in a crystal interfere constructively (see figure).
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Question
7/10
4 / -1
In Fraunhofer diffraction experiment, L is the distance between screen and the obstacle, b is the size of obstacle and λ is wavelength of incident light. The general condition for the applicability of raunhofer diffraction is
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Question
8/10
4 / -1
Following diffraction pattern was obtained using a diffraction grating using two different wavelengths λ
1
and λ
2
. With the help of the figure identify which is the longer wavelength and their ratios?
Correct
Wrong
Skipped
A
λ
2
is longer than λ
1
and the ratio of the longer to the shorter wavelength is 1.5
Correct
Wrong
Skipped
B
λ
1
is longer than λ
2
and the ratio of the longer to the shorter wavelength is 1.5
Correct
Wrong
Skipped
C
λ
1
and λ
2
are equal and their ratio is 1.0
Correct
Wrong
Skipped
D
λ
2
is longer than λ
1
and the ratio of the longer to the shorter wavelength is 2.5
Question
9/10
4 / -1
In a Fraunhofer diffraction experiment at a single slit using a light of wavelength 400 nm, the first minimum is formed at an angle of 30°. The directipn θ of the first secondary maximum is given by
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Question
10/10
4 / -1
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
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Solutions
Re-attempt
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