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Chemistry Test 126
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Chemistry Test 126
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  • Question 1/10
    4 / -1

    The functional group, which is found in an amino acid is:

    Solutions

    The functional group which is found in an amino acid are COOH and NH3 (amine group). So every amino acid has a central carbon with a H,R group (varies for each amino acid), a carboxylic group and an amine group. These groups are joined to a single (aliphatic) carbon. The carbon directly attached to a carboxyl group is the alpha position, so the amino acids in proteins are all alpha-amino acids.

     

  • Question 2/10
    4 / -1

    Ammonia Forms the complex ion  with copper ions in alkaline solution but not in acidic solutions. What is the reason for it?

    Solutions

    Ammonia acts as a ligand as it donates its lone pair of electrons to Cu2+ ions to form [Cu(NH3)4]2+ complex. This is possible in basic medium. In an acidic medium, the lone pair of electrons present on ammonia is donated to proton to form ammonium ion which is not a ligand and cannot form a complex with Cu2+ ions.

     

  • Question 3/10
    4 / -1

    The most suitable reagent for the conversion of RCH2OH→RCHO is:

    Solutions

    its an oxidation reaction.

    Pyridinium chlorochromate is a mild oxidising agent that oxidises primary alcohol to aldehydes and secondary alcohols to ketones. It does not affect any other functional group and therefore has high selectivity for oxidation of alcohols. Whereas acidic permanganate, acidic dichromate, chromic anhydride in glacial acetic acid are strong oxidising agents and can do further oxidation to carboxylic acid.

    The most suitable reagent for RCH2OH→RCHO is pyridinium chlorochromate (PCC).

     

  • Question 4/10
    4 / -1

     

    AgNO3 (aqueous) was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot of conductance (Λ) versus the volume of AgNO3 is:

    Solutions

    As AgNO3 is added to the solution, KCl will be displaced according to the following reaction.

    AgNO3(aq)+KCl(aq)⟶AgCl(s)+KNO3(aq)

    For every mole of KCl displaced from solution, one mole of KNO3 comes in solution resulting in almost constant conductivity. As the endpoint is reached, added AgNO3 remain in solution increasing ionic concentration, thus conductivity increases.

     

  • Question 5/10
    4 / -1

    Which of the following is tetrabasic acid?

    Solutions

    Tetrabasic acid means acids having 4− replaceable hydrogen atoms.

    Pyro phosphoric acid ⟶H4P2O7

    Ortho phosphoric acid ⟶H3PO4

    Hypo phosphorus acid ⟶H3PO

    Meta phosphoric acid ⟶(HPO3)n

    Here, pyro phosphoric acid, H4P2O7 have 4 removable H+ ions, thus it is a tetrabasic.

     

  • Question 6/10
    4 / -1

    A metal nitrate reacts with KI to give a black precipitate which on addition to an excess of KI converts into an orange colour solution. The cation of metal nitrate is:

    Solutions

    Bismuth nitrate, Bi(NO3)3, reacts with KI to give a black precipitate of Bil3, which on the addition of an excess of KI, dissolved to give an orange colour solution of K[Bil4] complex salt.

     

  • Question 7/10
    4 / -1

    Which kind of isomerism is exhibited by octahedral complex, [Co(NH3)4Br2]Cl?

    Solutions

    Octahedral Co(NH3)4Br2Cl shows ionisation and geometrical isomerism.

    In ionisation isomerism ligands shown in the coordination sphere and the anions present outside the coordination, sphere are exchanged with each other as follows:

    The coordination number of the central atom (cobalt) is six and the shape is octahedral, so it shows the following geometrical isomers.

     

  • Question 8/10
    4 / -1

    An exothermic chemical reaction occurs in two steps as follows:

    I. A+B→X( fast ) 

    II. X→AB (Slow)

    The progress of the reaction can be best represented by:

    Solutions

    The reaction occurring in two steps has two activation energy peaks. The first step being fast needs less activation energy. The second step being slow needs more activation energy. Therefore, the second peak will be higher than the first.

     

  • Question 9/10
    4 / -1

    Which of the following facts about the complex [Cr(NH3)6]Cl3 is wrong?

    Solutions

    The complex [Cr(NH3)6]Cl3 involved d2sp3 hybridization as it involves (n−1)d orbitals for hybridization. It is an inner orbital complex.

    The d-orbital involved in hybridization belongs to the penultimate shell due to the presence of a strong ligand.

     

  • Question 10/10
    4 / -1

    The pair of compounds having metals in their highest oxidation state is:

    Solutions

    In (MnO4),CrO2Cl2 oxidation states of Mn and Cr are +7 and +6 respectively.

    [NiCl4]2−,[COCl4] oxidation states of Ni and Co are +2 and +3 respectively.

    In [Fe(CN)6]3−,[CO(CN)6]3− oxidation states of Fe and Co are +3 and +3 respectively.

    In MnO2 and FeCl3 oxidation states of Mn and Fe are +4 and +3 respectively.
     

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