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Chemistry Test 132
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Chemistry Test 132
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  • Question 1/10
    4 / -1

    The cations present in 'A'

    Solutions

     

  • Question 2/10
    4 / -1

    20 g helium is compressed isothermally and reversibly at 27 °C from a pressure of 2 atmosphere to 20 atmosphere. The change in the value of heat energy change during the process is (R = 2 cal kelvin-1 mol-1)

    Solutions

     

  • Question 3/10
    4 / -1

    Which of the following type of compound is used to increase the hardness of the silicone polymer.

    Solutions

    Hydrolysis followed by condensation polymerization of RSiCl3 produces 3-D cross-linked silicones which are hard.

     

  • Question 4/10
    4 / -1

    Consider the reaction 2A + B →products, when the concentration of A alone was doubled, the half-life of the reaction did not change. When the concentration of B alone was doubled, the rate was not altered. The unit of rate constant for this reaction is

    Solutions

     

  • Question 5/10
    4 / -1

    The products A and B of the above reaction are respectively

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  • Question 6/10
    4 / -1

    0.066 g of a metal was deposited when a current of 2 ampere passed for 100 seconds through an aqueous solution of its metal ion. The equivalent mass of the metal is-

    Solutions

    Total charge passed in Coulombs = It = 2 X100 = 200 Coulombs
    200 Coulombs of charge deposits 0.066 g of metal.
    Equivalent mass of the metal is that mass of metal deposited by 1 Farad or 96500 Coulombs.
    Equivalent mass of metal

     

  • Question 7/10
    4 / -1

    A mixture of gaseous nitrogen and gaseous hydrogen attains equilibrium with gaseous Ammonia according to the reaction

    It is found that at equilibrium when temperature is 673 K , atmospheric pressure is 100, moles of gaseous nitrogen and gaseous hydrogen are in ratio 1:3 and mole percent of gaseous ammonia is 24 . The equilibrium constant Kp for the reaction at the above condition is-

    Solutions

     

  • Question 8/10
    4 / -1

    Solutions

     

  • Question 9/10
    4 / -1

    Study the following reactions and identify the reactant 'R'.

    Solutions

     

  • Question 10/10
    4 / -1

    A new carbon – carbon bond is formed in:

    Solutions

    New carbon-carbon bond is formed is Friedal Craft reaction and Reimer-Teimann reaction

     

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