d and f-Block Elements Test

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d and f-Block Elements Test - 21

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Question 1/13
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Only One Option Correct Type
Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
Which one of the following is an electronic configuration of thorium?

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A
[Rn] 5f¹6d¹7s²

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B
[Rn] 5f²6d²7s⁰

Correct

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C
[Rn] 5f²6d⁰7s²

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D
[Rn] 5f⁰6d²7s²

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Solutions

Thorium (Z = 90) have [Rn] 5f⁰6d²7s² configuration.
Question 2/13
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Which of the following is general electronic configuration of actinides?

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A
[Rn] 5f^0-146d^0-17s²

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B
[Rn] 5f^1-14 6d^0-147s²

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C
[Rn] 5f^0-146d²7s²

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D
[Rn] 5f¹6d²7s⁰

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Solutions

General EC = [Rn] 5f^1-146d^0-17s².
Question 3/13
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The actinoids Exhibit more member of oxidation states in general than the lanthanoids. This is because

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A
the 5f-orbitals are more buried than the 4f-orbita!s

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B
there is a similarity between 4f and 5f-orbitals in their angular part of the wave function

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C
the actinides are more reactive than the lanthanides

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D
the 5f-orbitals extend farther from the nucleus than the 4f-orbitals

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Solutions

The wide range of oxidation state of actinoids is due to the fact that the 5f, 6d and 7s energy levels are of comparable energies and all these three subshells can participate in comparison to lanthanoid. The 5f orbitals extend farther from the nucleus than the 4f orbitals.
Question 4/13
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Identify the incorrect statement among the following.

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A
All f-block elements belong to 3rd group

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B
Element curium (Z = 96) has 5f⁷ 6d¹7s²

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C
The actinides tarnish readily in air

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D
4f and 5f-orbitals are equally buried

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Solutions

4f electrons have greater shielding effect but 5f electrons have poor shielding effect.
Question 5/13
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In which 5f subshell is half-filled?

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A
Am and Cm

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B
Cm and Bk

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C
Cm and Cf

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D
No and Lr

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Solutions

Americium (2 = 95) and curium (Cm, Z = 96) have [Rn] 5f⁷6d⁰7s² and [Rn] 5f⁷6d¹7s² configuration, respectively.
Question 6/13
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Actinides

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A
are all synthetic elements

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B
include element 104

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C
are highly electropositive and reactive

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D
do not show variable oxidation state

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Solutions

Actinides are highly electropositive and reactive metals.
Question 7/13
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Which of the following is not an actinide?

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A
Curium

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B
Californium

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C
Uranium

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D
Rutherfordium

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Solutions

Actinoids are from thorium (Z = 90)to Lawrencium (Z = 103) in the Periodic table So, rutherfordium (Z = 104) is not an actinoid.
Question 8/13
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The compound used in enrichment of uranium for nuclear power plant is

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A
U₃O₈

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B
UF₆

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C
UCI4

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D
UO₂(NO₂)₂

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Solutions

UF₆ is used in enrichment of uranium for nuclear power plant.
Question 9/13
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Which one of the following shows oxidation state upto + 7?

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A
Am

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B
Pu

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C
U

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D
Cm

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Solutions

Plutonium (Z = 94) have [Rn] 5f⁶6d⁰7s² configuration and show oxidation state upto +7.
Question 10/13
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The general electronic configuration of actinides is (n - 2) f^1-14 (n - 1) d0^-1 ns2.
Which one of the following actinides has one electron in 6d-orbital?

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A
Cm (Z = 96)

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B
Lr (Z = 103)

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C
Np (Z = 93)

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D
All of these

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Solutions

Cm(Z = 96)have [Rn] 5f⁷6d¹7s²,
Lr (Z = 103) have [Rn] 5f¹⁴6d¹7s²
Np (Z = 93) have [Rn] 5f⁴6d¹7s²
Question 11/13
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Matching List Type
Direction (Q. No. 11) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

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A
a

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B
b

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C
c

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D
d

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Solutions

(i)→ (q), (ii) → (s), (iii) → (r) , (iv) → (p)
Question 12/13
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Statement Type
Direction (Q. Nos. 12 and 13) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.
Q.
Statement I : Actinides show a large number of oxidation state whereas lanthanides show a limited number of oxidation state.
Statement Il : Energy gap between 4f, 5d and 6s subshells is small whereas that between 5f, 6d and 7s subshell is large.

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A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

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B
Statement I is correct but Statement II is incorrect

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C
Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I

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D
Statement II is correct but Statement I is incorrect

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Solutions

statement ll is wrong
The energy gap among 4f, 5d and 6s is large where as the energy gap among 5f, 6d and 7s is small.
Question 13/13
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Statement I : Actinides form relatively less stable complexes as compared to lanthanides.
Statement II : Actinides can utilise their 5f -orbitals along with 6d-orbitals in bonding but lanthanides do not use their 4f-orbitals for bonding.

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A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

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B
Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I

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C
Statement I is correct but Statement II is incorrect

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D
Statement II is correct but Statement I is incorrect

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Solutions

Acitinides form relatively more stable complexes as compared to lanthanides.

Question 1/13

[Rn] 5f16d17s2

[Rn] 5f26d27s0

[Rn] 5f26d07s2

[Rn] 5f06d27s2

Question 2/13

[Rn] 5f0-146d0-17s2

[Rn] 5f1-14 6d0-147s2

[Rn] 5f0-146d27s2

[Rn] 5f16d27s0

Question 3/13

the 5f-orbitals are more buried than the 4f-orbita!s

there is a similarity between 4f and 5f-orbitals in their angular part of the wave function

the actinides are more reactive than the lanthanides

the 5f-orbitals extend farther from the nucleus than the 4f-orbitals

Question 4/13

All f-block elements belong to 3rd group

Element curium (Z = 96) has 5f7 6d17s2

The actinides tarnish readily in air

4f and 5f-orbitals are equally buried

Question 5/13

Am and Cm

Cm and Bk

Cm and Cf

No and Lr

Question 6/13

are all synthetic elements

include element 104

are highly electropositive and reactive

do not show variable oxidation state

Question 7/13

Curium

Californium

Uranium

Rutherfordium

Question 8/13

U3O8

UF6

UCI4

UO2(NO2)2

Question 9/13

Am

Pu

U

Cm

Question 10/13

Cm (Z = 96)

Lr (Z = 103)

Np (Z = 93)

All of these

Question 11/13

a

b

c

d

Question 12/13

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

Statement I is correct but Statement II is incorrect

Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I

Statement II is correct but Statement I is incorrect

Question 13/13

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I

Statement I is correct but Statement II is incorrect

Statement II is correct but Statement I is incorrect

[Rn] 5f¹6d¹7s²

[Rn] 5f²6d²7s⁰

[Rn] 5f²6d⁰7s²

[Rn] 5f⁰6d²7s²

[Rn] 5f^0-146d^0-17s²

[Rn] 5f^1-14 6d^0-147s²

[Rn] 5f^0-146d²7s²

[Rn] 5f¹6d²7s⁰

Element curium (Z = 96) has 5f⁷ 6d¹7s²

U₃O₈

UF₆

UO₂(NO₂)₂