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Analytical Chemistry Test - 5
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Analytical Chemistry Test - 5
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  • Question 1/10
    4 / -1

    Which sulphide is soluble in (NH4)2 CO3?

    Solutions

    As2S3 forms complex with ( NH4)2 CO3

     

  • Question 2/10
    4 / -1

    A precipitate of the following would be obtained when HCl is added to a solution of stannous sulphide (SnS) in yellow ammonium sulphide:

    Solutions

     

  • Question 3/10
    4 / -1

    Conc. HNO3 is added before proceeding to test for group III members. This is to:

    Solutions

    HNO3 oxidises Fe2+ to Fe3+ otherwise Fe2+ is not completely precipitated as hydroxide

  • Question 4/10
    4 / -1

    The compound insoluble in acetic acid is:

    Solutions

    Calcium oxalate will not dissolve in acetic acid (weak acid) but only in strong acid

     

  • Question 5/10
    4 / -1

    Of the following sulphides which one is insoluble in dilute acids but soluble in alkalies?

    Solutions

    It is an acidic salt

     

  • Question 6/10
    4 / -1

    Which of the following radicals will not be precipitated by passing H2S in concentrated acid solution?

    Solutions

    As cadmium belongs to the IInd group and is precipitated as sulphide and not as chloride

     

  • Question 7/10
    4 / -1

    H2S will precipitate the sulphides of all the metals from the solution of chlorides of Cu,Zn and Cd, if ?

    Solutions

    Due to common ion effect as

     

  • Question 8/10
    4 / -1

    Which one among the following pairs of ions cannot be separated by H2S in dilute hydrochloric acid?

    Solutions

    Both will precipitate as sulphide.

     

  • Question 9/10
    4 / -1

    Pb (CH3COO)2 gives….colour with H2S ?

    Solutions

     

  • Question 10/10
    4 / -1

    Sodium carbonate cannot be used in place of ammonium carbonate for the precipitation of the fifth group radicals because:

    Solutions

     

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