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Analytical Chemistry Test - 7
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Analytical Chemistry Test - 7
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  • Question 1/10
    4 / -1

    200 ml 0.6 N H2SO4 and 100 ml of 0.3N HCl are mixed together. Acidic normality of the resultant solution is:

    Solutions

    N1V1 + N2V2 = N3V3

    = 300 ml

    ∴ N3 = 0.5 N

     

  • Question 2/10
    4 / -1

    A mixture containing Cd2+ and Ni2+ can be separated for identification by:

    Solutions

    Cu2+ will be precipitated as CuS in acidic medium where as Ni2+ is not precipitated.

     

  • Question 3/10
    4 / -1

    Which one of the following sulphides is only completely precipitated when the acidic solution is made dilute?

    Solutions

    Sulphide having high ionic product are completely precipitated in acidic medium. CdS has maximum ionic product hence it is completely precipitated.

     

  • Question 4/10
    4 / -1

    25 ml of a solution of Na2CO3 having a specific gravity of 1.25 required 32.9 ml of a solution of HCl containing 109.5grams of the acid per litre for complete neutralization. Calculate the volume of 0.84 N – H2SO4 that will be completely neutralized by 125 grams of the Na2CO3 solution:

    Solutions

    N1 V1 = N2 V2

     

  • Question 5/10
    4 / -1

    In order to prepare one litre normal solution of KMnO4, how many gm of KMnO4 are required, if the solution is to be used in acid medium for oxidation:

    Solutions

    In acidic medium 2 molecules of KMnO4 gives 5 atoms of oxygen

     

  • Question 6/10
    4 / -1

    How many grams of NaOH are equivalent to 100 ml of 0.1 N oxalic acid?

    Solutions

     

  • Question 7/10
    4 / -1

    0.126g of an acid requires 20 ml of 0.1N NaOH for complete neutralization. The equivalent weight of the acid is:

    Solutions

    20 ml of 0.1N NaOH neutralize 20 ml of 0.1N acid Weight of acid = 0.216 g

     

  • Question 8/10
    4 / -1

    0.16 gm of a dibasic acid required 25 ml of decinormal NaOH solution for complete neutralization. The molecular weight of the acid is:

    Solutions

     

  • Question 9/10
    4 / -1

    0.1914g of an organic acid is dissolved in approx. 20 ml of water. 25 ml of 0.12 N NaOH required for the complete neutralization of the acid solution. The equivalent weight of the acid is:

    Solutions

     

  • Question 10/10
    4 / -1

    1 gm of hydrogen is found to combine with 80 gms of bromine. 1 gm of calcium (valency 2) combines with 4 gms of bromine. The equivalent weight of calcium is:

    Solutions

    4 gms of Br2 combines with 1 gm of Ca

    ∴ 80 gms of Br combines with 1/4 × 80 = 20

    Therefore, equivalent wt of Ca = 20

     

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