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Elasticity Test - 5
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Elasticity Test - 5
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  • Question 1/10
    1 / -0

    The Marina trench is located in the Pacific Ocean, and at one place it is nearly eleven km beneath the surface of the water. The water pressure at the bottom of the trench is about 1.1 × 108 Pa. A steel ball of initial volume 0.32 m3 is dropped into the ocean and falls to the bottom of the trench. What is the change in the volume of the ball when it reaches the bottom? 

    [Given : Bsteel = 1.6 × 1011 N m-2]

    Solutions

    Hint: Apply the concept of Bulk modulus.

    The pressure at the bottom, P=1.1 × 108 Pa

    Initial volume of steel ball = V = 0.32 m3

    The bulk modulus of steel, B = 1.6×1011 N m−2

    Step 1: Use the formula of the bulk modulus.

     

  • Question 2/10
    1 / -0

    Select the correct alternative(s).

    Solutions

    Work done by elastic forces in a circular loop is not zero always so elastic forces are not always conservative.

     

  • Question 3/10
    1 / -0

    Which of the following affects the elasticity of a substance?

    Solutions

    Change in temperature, impurity in substance, hammering affects the elasticity of substance.

     

  • Question 4/10
    1 / -0

    Select the wrong definition.

    Solutions

    Plastics are materials that can be shaped and molded easily. Plastics become easier to mold and shape when they're hot, and they melt when they get enough.

     

  • Question 5/10
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    A uniform cubical block is subjected to volumetric compression, which decreases its each side by 2%. The Bulk strain produced in it is

    Solutions

     

  • Question 6/10
    1 / -0

    Due to the addition of impurities, the modulus of elasticity:

    Solutions

    Addition of impurities effects the elasticity as follows. If impurities added is more elastic then the material becomes more elastic and vice-versa

     

  • Question 7/10
    1 / -0

    A load of 2 kg produces an extension of 1 mm in a wire of 3 m in length and 1 mm in diameter. The Young's Modulus of wire will be

    Solutions

    The applied force (load) = F = mg

    = 2×9.8 = 19.6 N

    diameter = 1mm = 1×10−3 m

    ⇒ radius = d/2 = 0.5 × 10−3 m

    Area = 3.14×0.25×10−6 m2

     = 0.785×10−6

     

  • Question 8/10
    1 / -0

    The value of Young's Modulus for a perfectly rigid body is

    Solutions

    Since for perfectly rigid body. Strain produced will be zero.

    Young's modulus is given by

     

  • Question 9/10
    1 / -0

    A spherical ball contracts in a volume by 0.01% when subjected to a normal uniform pressure of 100 atm. The Bulk modulus of its material is

    Solutions

    Since the spherical contracts by 0.01%

     

  • Question 10/10
    1 / -0

    A metallic rod of length l and cross-sectional area A is made of a material of Young's Modulus Y. If the rod is elongated by an amout y, then the work done is proportional to

    Solutions

     

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