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Elasticity Test - 7
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Elasticity Test - 7
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  • Question 1/10
    1 / -0

    Work done by restoring force in a wire within elastic limit is -10 J. Maximum amount of heat produced in the wire is

    Solutions

    Since work done is converted into heat. Maximum amount of heat produced in the wire is 10 J

     

  • Question 2/10
    1 / -0

    The work done per unit volume to stretch the length of area of cross-section 2 mm2 by 2% will be [Y=8×1010 N/m2]

    Solutions

    We know that

     

  • Question 3/10
    1 / -0

    Which one of the following statements is wrong?

    Solutions

    Young Modulus for a perfectly rigid body is infinity, and not zero, so that statement is wrong.

     

  • Question 4/10
    1 / -0

    On stretching some substances, why is permanent elongation caused?

    Solutions

    Permanent elongation is caused for perfectly plastic material.

     

  • Question 5/10
    1 / -0

    On abruptly withdrawing the stretching force acting on a wire, its temperature will:

    Solutions

    Work done on the wire to strain will be stored as energy which is converted to heat therefore the temperature increases.

     

  • Question 6/10
    1 / -0

    The temperature of the wire is doubled. Young's modulus of elasticity:

    Solutions

    Hint: Young's modulus is the property of the material of the wire.

    Step 1: Find the change in length of the wire.

    We know that with an increase in temperature, the length of a wire changes as; L= Lo(1 + αΔT)

    where ΔT is the change in the temperature, L0 is the original length, αα is the coefficient of linear expansion and Lt is the length at temperature T.

    Now, we can write, ΔL = Lt − Lo = LoαΔT

    Step 2: Find Young's modulus.

     

  • Question 7/10
    1 / -0

    Consider two cylindrical rods of identical dimensions, one of rubber and the other of steel. Both the rods are fixed rigidly at one end of the roof. A mass M is attached to each of the free ends at the centre of the rods.

    Solutions

    Hint: The elongation of a material depends on its elastic properties.

    Step 1: Find the comparative change in the shape of the rods.

    A mass M is attached at the centre. As the mass is attached to both the rods, both rods will be elongated. Due to the different elastic properties of the material, rubber changes shape also.

     

  • Question 8/10
    1 / -0

    For an ideal liquid

    Solutions

    For an ideal liquid, bulk modulus is infinite and shear modulus is zero.

     

  • Question 9/10
    1 / -0

    A copper and a steel wire of the same diameter are connected end to end. A deforming force F is applied to this composite wire which causes a total elongation of 1cm. The two wires will have then

    Solutions

    stress = A/F​

    As each wire is of same diameter, hence the area of cross section is same for both the wires. As both the wires have the same force (F) and same area of cross-section therefore, stress is same for both the wires

    As young's modulus, Y = stress / strain ​or Strain = stress​ / Y

    As Y is different for both the wires and stress is same for both the wires, therefore strains is different for both the wires.

     

  • Question 10/10
    1 / -0

    Bridges are declared unsafe after a long time of their use due to:

    Solutions

    If the bridge is used for a long time, due to alternate cycles of stress and strain, the bridge gradually loses its elastic properties and finally reaches a condition called elastic fatigue.

     

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