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For a reaction A → B
The rate of the reaction is
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As concentration of product is not changing with time, the reaction is at equilibrium.
The equilibrium constant for the reaction, N2 (g) + O2 (g) ⇌ 2 NO (g) is 4 × 10-4 at 2000 K. In presence of a catalyst, equilibrium is attained ten times faster. Therefore, the equilibrium constant, in presence of the catalyst, at 2000 K is
A catalyst does not affect the value of Equilibrium constant ( Keq) it only reduces the time of attainment of equilibrium. In fact, it does not even change the position of equilibrium.
In which of the following cases does the reaction go farthest to completion
Extent of reaction depends upon value of Keq. Higher the Keq higher is the extent of reaction.
For a reaction, N2 + 3H2 ⇌ 2NH3 , the value of Kc would depend upon
The equilibrium constant KC of a reaction depends only on temperature and nature of reactants.
Which is not correct for an exothermic reaction
For exothermic Reaction ∆H° < 0hence slope > 0
For the given reaction, 2A (s) + B (g) ⇌ C (g) + 2D (s) + E (s) the degree of dissociation of B was found to be 20% at 300 K and 24% at 500 K. The rate of forward reaction
As degree of dissociation, α increases with increase in temperature of reaction, the reaction is endothermic in nature. Therefore, on increase in temperature, Rate of forward reaction increases.
Also, ∆ng = 0 for the reaction, pressure has no effect on equilibrium.
The gas A2 in the left flask allowed to react with gas B2 present in right flask as
A2 (g) + B2 (g) ⇌ 2AB (g) ; Kc = 4 at 27°C
What is the concentration of AB when equilibrium is established?
For the gas phase reaction, 2NO(g) ⇌ N2 (g) + O2 (g), ∆H = –43.5 kcal, which one of the following is true for N2(g) + O2(g) ⇌ 2NO(g)
The given reaction, N2(g) + O2(g) ⇌ 2NO (G) is endothermic. Therefore, according to Le Chatelier’s principle, high temperature favours forward reaction and hence K increases as T increases or K decreases as T decreases.
The reactions, PCl5 (g) ⇌ PCl3 (g) + Cl2 (g) and COCl2 ⇌ CO (g) + Cl2 (g) are simultaneously in equilibrium in an equilibrium box at constant volume. A few moles of CO(g) are later introduced into the vessel. After some time, the new equilibrium concentration of
If some CO is added, the reaction (ii) will move in backward direction, this results in the decrease in concentration of Cl2 and reaction (i) will move in forward 6 direction, hence concentration of PCl5 will definitely decrease. Concentration of COCl2 will increase and so will be the concentration of PCl3.
For the decomposition of PCl5 g in a closed vessel, the degree of dissociation is 'x' at a total pressure 'P'.
Which among the following relations is correct?
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