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Reflection Test - 4
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Reflection Test - 4
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  • Question 1/10
    1 / -0

    A person AB of height 170 cm is standing in front of a plane mirror. His eyes are at height 164 cm. At what distance from P should a hole be made in the mirror so that he cannot see his hairs?

    Solutions

    To see the image of hair, the rays incident from hair must reach the eye of the person after reflection.

    Let the hole be made at a point M on the mirror where light coming from hair is reflected.

     

    From the geometry of the diagram,
    PM = BC
    ⇒ PM = BE + CE

     

  • Question 2/10
    1 / -0

    The figure shows two parallel plane mirrors placed 10cm apart. An object O is placed 7cm from mirror M1. Then the distance of final image formed from mirror M1 is

    Solutions

    Only M1 is effective in making image since light rays will not fall on M2

     

  • Question 3/10
    1 / -0

    A spherical concave mirror of focal length 10 cm is cut in two equal halves and is separated by a distance 4 mm as shown. A small object is kept at 30 cm from the mirrors and between the two halves as shown.

    The distance between the images by halves of mirror will be

    Solutions

     

  • Question 4/10
    1 / -0

    A man is sitting in a room at 2 m from a wall W1 wants to see the full height of the wall W2 behind him 4 m high and 6 m away from the facing wall W1. What is the minimum vertical length of mirror on the facing wall required for the purpose?

    Solutions

    Let the min. length of mirror be L

     

  • Question 5/10
    1 / -0

    When a plane mirror is placed horizontally on a level ground at a distance of 60 m from the foot of a tower, the top of the tower and its image in the mirror subtend an angle of 90o at the eye. The height of the tower will be

    Solutions

     

  • Question 6/10
    1 / -0

    A ray of light fails on a plane mirror. When the mirror is turned, about an axis which is at right angle to the plane of the mirror through 20o the angle between the incident ray and new reflected ray is 45o. The angle between the incident ray and original reflected ray was therefore:

    Solutions

    If mirror is turned, about an axis perpendicular to plane of mirror, then there will be no change in incident angle and reflected angle so angle between incident & reflected rays after rotation will be same as before.

     

  • Question 7/10
    1 / -0

    Find the distance between the object and its doubly magnified real image by a concave mirror of focal length f .

    Solutions

     

  • Question 8/10
    1 / -0

    The reflection surface of a plane mirror is vertical. A particle is projected in a vertical plane which is also perpendicular to the mirror. The initial velocity of the particle is 10 m/s and the angle of projection is 600. The point of projection is at a distance 5m from particle moves towards the mirror . just before the particle touches the mirror. the velocity of approve of the particle and the image is :

    Solutions

    Horizontal component of the velocity is 10cos(60)=5

    And vertical component is 10sin(60) = 8.66

    The participial will touch the mirror after = 5/5 ​= 1s

    In this time vertical velocity will be V = u−gt = 8.66 − 9.8 × 1 = −1.14

    Now the relative velocity will be due to horizontal component of the particle .

    Since the vertical velocity will be same .

    So, te relative velocity of the particle is 2 × 5 = 10m/s.

     

  • Question 9/10
    1 / -0

    The radius of curvature of a plane mirror of length 40 cm is:

    Solutions

    The radius of curvature of a plane mirror is infinite.

     

  • Question 10/10
    1 / -0

    A rod 1.5 m long is placed along the principal axis of a convex mirror of focal length 60 cm. The near end of the rod is 1 m from the pole of the convex mirror. The length of the image of the rod is

    Solutions

     

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