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The reaction is as follows:
2H2 + O2 ------------> 2H2O
This means that for every 2 molecules of Hydrogen gas, one molecule of Oxygen is needed to make 2 molecules of water
To calculate the enthalpy of this reaction, we use the equation:
Enthalpy of reaction = (Enthalpy of products) - (Enthalpy of reactants)
The Enthalpy of Formations for each molecule are:
H2 = 0 kJ/mol
O2 = 0 kJ/mol
H2O = -285.83 kJ/mol
From the equation given earlier, we can put the numbers in and get
Enthalpy = -285.83 - (0+0)
This means Enthalpy of formation of water = -285.83 kJ/mol
Hence, the correct option is (C).