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Which of the following alkenes will react fastest with H2 under catalytic hydrogenation conditions?
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The reactivity order towards H2 is
cis > iso > trans i.e in option A the alkene is cis.
The heat of hydrogenation of 1-hexene is 126 When a second double bond is introduced in the molecule, the heat of hydrogenation of the resulting compound is 230 The resulting compound (diene) is
1,3 -hexadiene is a conjugated diene, hence it is more stable than the first compound. The heat of hydrogenation decreases as the stability of the molecule increases. The stability of 13 hexadiene is more than that of a compound which contain two double bonds.
Heat of hydrogenation of benzene is 51 kcal/mol and its resonance energy is 36 kcal/mol. Then the heats of hydrogenation of cyclohexadiene and cyclohexene per mole respectively are
Total energy to break 3 bond in benzene is 87 [51+36].
So to break one bond i.e. in cyclohexaene is 87/3= 29 kcal/mol.
And to break 2 bond i.e.in cyclohexadiene is 29*2= 58 kcal/mole.
H2 gas is liberated at cathode and anode both by electrolysis of the following aq. solution except in :
At the cathode (C), water is reduced to hydroxide and hydrogen gas. The net process is the electrolysis of an aqueous solution of NaCl into industrially
Electrolysis of aqueous sodium chloride yields hydrogen and chlorine, with aqueous sodium. Chlorine gas bubbles out of the melt above the anode.
“10 volume” H2O2 means :
H2O2 is the special concentration terms.10 volume of H2O2 means that 1ml of H2O2 gives 10 ml of O2.
For example, if it was mentioned 30 volume of H2O2, then its means that 1ml of H2O2 gives 30ml of O2.
D2O (heavy water) and H2O differ in following except
Chemical properties won't change in case of isotopes. Therefore answer is D.
When 0.532 g of benzene (B.P. 80o C) is burnt in a constant volume system with an excess of oxygen, 22.3 KJ of heat is given out. ∆H for the combustion process is given by :
The work done by the system in a cyclic process involving one mole of an ideal monoatomic gas is 50 KJ/cycle, The heat absorbed by the system per cycle is
According to the first law of thermodynamics,
∆Q=∆U+∆W and for a cyclic process, change in internal energy(∆U) is zero. Hence ∆Q=∆W where ∆Q is the heat absorbed and ∆W is the work done. Therefore heat absorbed is 50 kJ
Which of the following is not correct ?
It should be equal to T, not (-T)
The heat released when NH4OH & HCl neutralise is :
Correct (-)
Wrong (-)
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