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Chemistry Test 135
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Chemistry Test 135
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  • Question 1/10
    4 / -1

    Which of the following hydrocarbons has the highest melting point?

    Solutions

    Melting point order is para > ortho > meta on basis of symmetry . So option b is correct.

     

  • Question 2/10
    4 / -1

    Propylene is passed through conc. H2SO4 and the prodcut thus obtained on hydrolysis with boiling water gives

  • Question 3/10
    4 / -1

    Reaction of ethene with Br2 in CCl4 gives

    Solutions

    When alkenes react with Br2 in presence of CCl4 it gives vicinnyl dibromides (1 2 dibromide )

     

  • Question 4/10
    4 / -1

    The major product obtained when isobutane is treated with chlorine in the presence of light is

    Solutions

    The major product is tert butyl chloride as firstly isobutylchloride is formed but then hydride shift takes place due to which chlorine shift to more stable tertiary carbocation and hence the product is tert butyl chloride.

     

  • Question 5/10
    4 / -1

    SO2 acts as

    Solutions

    SO2 can act as both oxidizing as well as reducing agent since it has +4 oxidation state which is exactly between

    its highest oxidation state +6 and lowest oxidation state +2 ,

    Thus it can change its oxidation number either from +4 to - 2(reduction) and +4 to + 6 (oxidation)

     

  • Question 6/10
    4 / -1

    Which one of the following leads to a redox reaction

    Solutions

    Redox reactions are characterized by the transfer of electrons between chemical species, most often with one species undergoing oxidation while another species undergoes reduction.

    2KI+Cl2​⟶2KCl +I2​​

    It is an example of a redox reaction.

    Hence, option C is correct.

     

  • Question 7/10
    4 / -1

    The compound contains atoms X,Y,Z. The oxidation number of X is 2, Y is 5 and Z is –2, a possible formula of the compound is

    Solutions

    The net charge on the compound should be zero. Or the sum of oxidation states = 0.

    Given: oxidation number of X is +2, Y is +5 and Z is -2.

    In XYZ2​:

    2+5+2×(−2)=+3

    In Y2​(XZ3​)2​:

    2×5+2×(2+3×(−2))=+2

    In X3​(YZ4​)2​:

    3×2+2×(5+4×(−2))=0

    In X3​(YZ4​)2​:

    3×2+2×(5+4×(−2))=0

    In X3​(Y4​Z)2​:

    3×2+2×(4×5−2)=42

    A compound contains atoms X, Y and Z . The oxidation number of X is +2 , Y is +5 and Z is -2.

    The possible formula of the compound is X3​(YZ4​)2​.

     

  • Question 8/10
    4 / -1

    Which of the following statements is correct regarding the structures of the  molecules

  • Question 9/10
    4 / -1

    How many allotropic forms of carbon are there ?

    Solutions

    Carbon has three well known allotropes which are graphite, daimond and buck minster fullerene.

     

  • Question 10/10
    4 / -1

    Graphite has a layered structure. The distance between the layers is

    Solutions

    Since the layers are only weakly attracted to each other, they can easily slide past one another. This is why graphite is used in pencil lead. The distance between layers is 335 pm. Carbon atoms in diamond are covalently bonded and are arranged in a three-dimensional tetrahedral structure.

     

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